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Anni [7]
3 years ago
6

A reaction was performed in which 4.0 g of cyclohexanol was reacted with an acid catalyst to obtain 2.8 g of cyclohexene. calcul

ate the percent yield for this reaction.

Chemistry
1 answer:
ioda3 years ago
5 0

Answer:

              %age Yield  =  85.36 %

Solution:

The Balance Chemical Reaction is as follow,

               C₆H₁₂O  +   Acid Catalyst    →    C₆H₁₀  +  Acid Catalyst + H₂O

According to Equation ,

              100 g (1 mole) C₆H₁₂O produces  =  82 g (1 moles) of C₆H₁₀

So,

                       4.0 g of C₆H₁₂O will produce  =  X g of C₆H₁₀

Solving for X,

                      X =  (4.0 g × 82 g) ÷ 100 g

                      X  =  3.28 g of C₆H₁₀   (Theoretical Yield)

As we know,

                     %age Yield  =  (Actual Yield ÷ Theoretical Yield) × 100

                     %age Yield  =  (2.8 g ÷ 3.28 g) × 100

                     %age Yield  =  85.36 %

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3 years ago
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How much faster will ammonia vapor travel across a room then carbon dioxide
FromTheMoon [43]

Answer:

D) 1.61 times faster

Explanation:

vrms_{NH3} = √(3)RTM

R constant= 0.08206

T=constant, so in this problem we dont need a value for it

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√(3)(0.08206)(17.031)= 2.047

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R constant= 0.08206

T=constant, so in this problem we dont need a value for it

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√(3)(0.08206)(44.01)= 3.29

Since we are trying to measure how much faster NH3 will be, we have to realize that mass and speed have an inverse relationship.

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6 0
3 years ago
How many liters of 0.305 M K3PO4 solution are necessary to completely react with 187 mL of 0.0184 M NiCl2 according to the balan
Mashutka [201]

Answer:

6.55 mL of K₃PO₄ are required

Explanation:

We need to propose the reaction, in order to begin:

2K₃PO₄ (aq) + 3NiCl₂(aq) →  Ni₃(PO₄)₂ (s) ↓ + 6KCl (aq)

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0.0184 M . 0.187L = 0.00344 moles of NiCl₂

Ratio is 3:2. Let's propose this rule of three:

3 moles of chloride react with 2 moles of phosphate

Then, 0.00344 moles of NiCl₂ will react with (0.00344 . 2) /3 = 0.00229 moles of K₃PO₄

M = mol / volume(L) → Volume(L) = mol/M

Volume(L) = 0.00229 mol / 0.350 M = 6.55×10⁻³L

We convert the volume from L to mL → 6.55×10⁻³L . 1000mL /1L = 6.55 mL

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