Find the perimeter of the figure
1 answer:
Answer:
Step-by-step explanation:
In order to find the Perimeter, we add all the segments up.
(2x-1)+(4x+3)+(x+2)+(2x+2)+(1/10x-1)+(2/5x)
=2x-1+4x+3+x+2+2x+2+1/10x-1+2/5x ⇔ Expand Parenthesis
=2x-1+4x+3+x+2+2x+2+1/10x-1+4/10x ⇔ Convert fractions into same
denominator
=(2x+4x+x+2x+1/0x+4/10x)+(3-1+2+2-1) ⇔ Put like terms together
=(9x+1/2x)+5 ⇔ Combine like terms
=9 1/2 x +5
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Answer:
∠ADB = γ/2 +90°
Step-by-step explanation:
Here's one way to show the measure of ∠ADB.
∠ADB = 180° - (α + β) . . . . . sum of angles in ΔABD
∠ADB + (2α +β) + γ + (2β +α) = 360° . . . . . sum of angles in DXCY
Substituting for (α + β) in the second equation, we get ...
∠ADB + 3(180° - ∠ADB) + γ = 360°
180° + γ = 2(∠ADB) . . . . . . add 2(∠ADB)-360°
∠ADB = γ/2 + 90° . . . . . . . divide by 2
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To find angles CXD and CYD, we observe that these are exterior angles to triangles AXB and AYB, respectively. As such, those angles are equal to the sum of the remote interior angles, taking into account that AY and BX are angle bisectors.
