Electrochemical cell representation for above reaction is,
Br-/Br2//I2/I-
Reaction at Anode: Br2 + 2e- → 2Br- (1)
Reaction at Cathode: 2I- → I2 + 2e- (2)
Standard reduction potential for Reaction 1 = Ered(anode) = 1.066 v
Standard reduction potential for Reaction 2 = Ered(cathode) = 0.535 v
Eo cell = Ered(cathode) - Ered(anode)
= 0.535 - 1.066
= -0.531v
Now, we know that ΔGo = -nF (Eo cell) ..............(3)
Also, ΔGo = RTln(K) ..........(4)
Equation 3 and 4 we get,
ln (K) = nF (Eo cell) / RT
= 2 X 96500 X (-0.531)/ (8.314 X 298)
∴ K = 1.085 X 10^-18.
The molecule of that compound! Hope this helps!
Answer:
4.5 g
Explanation:
The mass of 1 mol of water is 18.02 g.
![\text{Mass of H$_{2}$O} = \text{0.25 mol H$_{2}$O} \times \dfrac{\text{18.02 g H$_{2}$O}}{\text{1 mol H$_{2}$O}} = \textbf{4.5 g H$_{2}$O}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20H%24_%7B2%7D%24O%7D%20%3D%20%5Ctext%7B0.25%20mol%20H%24_%7B2%7D%24O%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B18.02%20g%20H%24_%7B2%7D%24O%7D%7D%7B%5Ctext%7B1%20mol%20H%24_%7B2%7D%24O%7D%7D%20%3D%20%5Ctextbf%7B4.5%20g%20H%24_%7B2%7D%24O%7D)
<span>Henry divides 1.060 g by 1.0 mL to find the density of his water sample.
</span>He should include THREE significant figures in the density value that hereports.
Gravitational potential energy is energy an object possesses because of its position in a gravitational field. The most common use of gravitational potential energy is for an object near the surface of the Earth where the gravitational acceleration can be assumed to be constant at about 9.8 m/s2.