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3 years ago

How does a material get a positive charge?

Chemistry

1 answer:

adoni [48]3 years ago

3 0

Answer:

positive charge comes from having more protons than electrons; negative charge comes from having more electrons than protons charge is quantized, meaning that charge comes in integer multiples of the elementary charge e

Explanation:

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A child and his mother both have blue eyes. They both have blue eyes because inherited traits of an organism are governed by the

cluponka [151]

The answer would probably be c.

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2 years ago

Read 2 more answers

PLZ HELP, Its The Nature of Oxidation and Reduction for chemistry

elixir [45]

Answer:

Oxidation is defined as the chemical process in which substance loses electron and hydrogen or gain oxygen while in the process of reduction, substance gains electron and hydrogen or loses oxygen.

So, from the given equation:

a. It is an oxidation reaction as Rb loses one elctron.

b. It is a reduction reaction as Te gains two electrons and become Te2-

c. It is a reduction reaction as H atom gains electrons.

d. It is an oxidation reaction as P loses 3 electrons.

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2 years ago

How many molecules are in 8.3 moles?

devlian [24]

1 mole=6.02 ×10

8.3 moles=?

8.3×6.02×10=499.66 molecules

therefore ghe no. of molecules = 499.66

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3 years ago

Why is it important for scientists and o make data tables

Yuki888 [10]

I think is important to make a data table because when you do the same experiment if you get the same its because your right?

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3 years ago

A chemist needs to determine the concentration of a sulfuric acid solution by titration with a standard sodium hydroxide solutio

Zigmanuir [339]

<u>Answer:</u> The concentration of original sulfuric acid solution is 1.62 M

<u>Explanation:</u>

Let the original concentration of sulfuric acid be 'x' M

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated sulfuric acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted sulfuric acid solution

We are given:

$M_1=xM\\V_1=25.00mL\\M_2=?M\\V_2=250.0mL$

Putting values in above equation, we get:

$x\times 25.00=M_2\times 250.0\\\\M_2=\frac{x\times 25.0}{250}=\frac{x}{10}$

Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=2\\M_1=\frac{x}{10}M\\V_1=10.00mL\\n_2=1\\M_2=0.1790M\\V_2=18.07mL$

Putting values in above equation, we get:

$2\times \frac{x}{10}\times 10.00=1\times 0.1790\times 18.07\\\\x=\frac{1\times 0.1790\times 18.07\times 10}{2\times 10.00}=1.62M$

Hence, the concentration of original sulfuric acid solution is 1.62 M

5 0

3 years ago