I believe it would be 1.660539040 × 10−24 gram.
Answer:
1.395J/g°C
Explanation:
The following were obtained from the question:
Q = 6527J
M = 312g
ΔT = 15°C
C =?
Q = MCΔT
C = Q/MΔT
C = 6527/(312 x 15)
C = 1.395J/g°C
The specific heat capacity of the substance is 1.395J/g°C
Complete question is;
A drop of water has a volume of approximately 7 × 10⁻² ml. How many water molecules does it contain? The density of water is 1.0 g/cm³.
This question will require us to first find the number of moles and then use avogadro's number to get the number of water molecules.
<em><u>Number of water molecules = 2.34 × 10²¹ molecules</u></em>
We are given;
Volume of water; V = 7 × 10⁻² ml
Density of water; ρ = 1 g/cm³ = 1 g/ml
Formula for mass is; m = ρV
m = 1 × 7 × 10⁻²
m = 7 × 10⁻² g
from online calculation, molar mass of water = 18.01 g/mol
Number of moles(n) = mass/molar mass
Thus;
n = (7 × 10⁻²)/18.01
n = 3.887 × 10⁻³ mol
from avogadro's number, we know that;
1 mol = 6.022 × 10²³ molecules
Thus,3.887 × 10⁻³ mol will give; 6.022 × 10²³ × 3.887 × 10⁻³ = 2.34 × 10²¹ molecules
Read more at; brainly.in/question/17990661
Particle is more than an atom - a particle I beleive implies either a diatomic gas or just a plain old unbonded noble gas atom? hope this helped.
Your answer is $20,480.
Hope this Helped!
<h3>Also here is the explanation: </h3><h3>https://www.symbolab.com/solver/equation-calculator/x%3D32000%5Cleft(.8%5Cright)%5E%7B2%7D</h3>
