Increase, because you need heat to melt a solid to a liquid, so the temperature will have to get greater.
Answer:
The orbital shapes are actually representation of (Ψ)2 all over the orbit simplified ... ψnlml(r,θ,ϕ)=Rnl(r)Ymll(θ,ϕ) , ... and thus it is directly linked to the angular and radial nodes. ... for different quantum values(which can be assigned to different orbitals are ) .... The two types of nodes are angular and radial.
Explanation:
hope it helps
It's A. volume
Pressure =
![\frac{moles * const * temperature}{volume}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bmoles%20%2A%20const%20%2A%20temperature%7D%7Bvolume%7D%20)
with const depends on the chosen unit of volume
I think so...
The balanced chemical reaction is:
<span>CuCl2 + 2Na → 2NaCl + Cu
We are given the amount of sodium to be used up in the reaction. This will be the starting point for our calculations.
15 g Na ( 1 mol / 22.99 ) ( 1 mol Cul2 / 2 mol Na ) (134.45 g / 1 mol ) = 43.86 g CuCl2 needed to be able to obtain the maximum amount of copper.</span>
Answer:
![V_2=313.71\ cm^3](https://tex.z-dn.net/?f=V_2%3D313.71%5C%20cm%5E3)
Explanation:
Given that,
Initial volume, ![V_1=525\ cm^3](https://tex.z-dn.net/?f=V_1%3D525%5C%20cm%5E3)
The pressure changes from 73.2 kPa to 122.5 k.Pa.
We need to find the new volume occupied by the air. Let it is V₂. It can be calculated using Boyle's law such that,
![P_1V_1=P_2V_2\\\\V_2=\dfrac{P_1V_1}{P_2}\\\\V_2=\dfrac{73.2\times 525}{122.5}\\\\V_2=313.71\ cm^3](https://tex.z-dn.net/?f=P_1V_1%3DP_2V_2%5C%5C%5C%5CV_2%3D%5Cdfrac%7BP_1V_1%7D%7BP_2%7D%5C%5C%5C%5CV_2%3D%5Cdfrac%7B73.2%5Ctimes%20525%7D%7B122.5%7D%5C%5C%5C%5CV_2%3D313.71%5C%20cm%5E3)
So, the new volume is
.