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umka2103 [35]
3 years ago
14

Write x^2 - 6x + 7= 0 in the form (x-a)^2 b, where a and b are intergers.

Mathematics
1 answer:
dimaraw [331]3 years ago
4 0

Answer:

(x-3)^2=2

Step-by-step explanation:

{x}^{2}  - 6x + 7 = 0 \\ adding \: 2 \: both \: sides \\  {x}^{2}  - 6x + 7 + 2 = 0 + 2 \\  {x}^{2}  - 6x + 9 =  2 \\  {x}^{2}  - 6x +  {(3)}^{2}  =  2 \\ (x - 3) ^{2}  = 2

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