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MaRussiya [10]
3 years ago
5

Help guys plz I don’t understand

Mathematics
1 answer:
vladimir2022 [97]3 years ago
4 0
1. Line segment
2. Right angle
3. Obtuse
4. Ray
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6r + 7 = 13 + 7r what is r
kumpel [21]

Answer:

6r+7=13+7r

6r+7=7r+13

6r+7−7r=7r+13−7r

−r+7=13

−r+7−7=13−7

−r=6

\frac{-r}{-1} = \frac{6}{-1}

r=−6

Step-by-step explanation:

:) This is the answer

6 0
3 years ago
Read 2 more answers
The base of a triangle is 9 inches more than 3 times the height. if the area of the triangle is 105 square inches, find the base
wolverine [178]
So to solve you need to set up equations, Using h as the height. So the base is 9 inches more  (+9)  than 3 times the height (3h) so 3h+9 equals the base. You have the area so you need to plug in the equation for the base and h for height and divide it all by 2. h(3h+9)/2=105. after you solve that and get h by itself you should get h= 7 and the b= 30 
4 0
3 years ago
Which of the following is being constructed in the image.
Sliva [168]

Answer:

  3. a line perpendicular to a given line through a point not on the line

Step-by-step explanation:

The point not on the line suggests that choices 1 and 3 are possibilities. The fact that the dotted line is not parallel (and is perpendicular) to the solid line suggests that choice 3 is applicable and choice 1 is not.

The short arcs are equidistant from the end points of the chord that intercepts the larger arc. Hence the line through the crossing point of the short arcs and the point on the other side of the line will be the perpendicular bisector of the chord, and will be perpendicular to the solid line. Creating that perpendicular is likely the purpose of the construction.

5 0
3 years ago
LOL 3 more to gooo . find the value of x
garri49 [273]

Answer:

17

Step-by-step explanation:

These two angles add up to 180, so we can set up an equation. 5x-23+7x-1=180. Now we combine like variables, getting 12x-23-1=180. We add 23 to both sides, and get 12x-1=203. Then we add 1 to both sides, getting 12x=204. Finally we divide by 12 on both sides, with our result as x=17.

8 0
3 years ago
Find the critical numbers sin^2x+cosx 0 < x< 2pi
ryzh [129]
\bf sin^2(x)+cos(x)\iff [sin(x)]^2+cos(x)\\\\
-----------------------------\\\\
\cfrac{dy}{dx}=2sin(x)cos(x)-sin(x)\implies 0=2sin(x)cos(x)-sin(x)
\\\\\\
0=sin(x)[2cos(x)-1]\implies 
\begin{cases}
0=sin(x)\\
sin^{-1}(0)=\measuredangle x\\
\pi \\
----------\\
0=2cos(x)-1\\\\ \frac{1}{2}=cos(x)\\\\ cos^{-1}\left( \frac{1}{2} \right)=\measuredangle x\\\\ \frac{\pi }{3},\frac{5\pi }{3}
\end{cases}
5 0
4 years ago
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