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Ann [662]
3 years ago
15

Create a Y and X table using the expression Y= -2x +5

Mathematics
1 answer:
dlinn [17]3 years ago
5 0
When x=1, y is 3
When x=2, y is 1
When x=3, y is -1
When x=4, y is -3
When x=5, y is -5
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All of the following expressions simplify to -4x + 9, except
Alla [95]
What are the options for the expressions?
6 0
3 years ago
Kylie needs to pack her baton for a color-guard competition. The baton is 38 inches long. Will it fit in a rectangular box with
poizon [28]

Answer:

The diagonal is 39.54 in

Step-by-step explanation:

First we use the Pythagorean theorem to calculate the length of the diagonal of the base.

If the base measures 13 inches by 35 inches then the diagonal is:

c = \sqrt{13^2 +35^2}\\\\c= 37.34\ in

Now we use the Pythagorean theorem again to find the diagonal of the cube.

If the height of the box is 13 inches and the diagonal of the base is 37.34 inches then the diagonal of the cube will be

z = \sqrt{37.34^2 +13^2}\\\\z= 39.54\ in

The baton will fit in the box if it is placed in the direction of the diagonal of the cube, since:

39.54\ in > 38 inches

7 0
3 years ago
Help please please please please please<br> 6th &amp; 7th
raketka [301]

First lets start with number six. The only way to solve this is if you determine what "a" and "b" are using the first log they have given to you. log_a_ba=\frac{1}{3}

The first variable that I solved for was "a" and a=e^\frac{in(b)}{2}[tex]{[tex]  0}

The same is also true for "b", but when you put both "a" and "b" together the only combination that I have found to work is a=\frac{1}{2} , b=\frac{1}{4}

Next you plug these numbers in for "a" and "b" on the second equation to get something that looks like this: log_\frac{1}{2}_*_\frac{1}{4} (\frac{\sqrt{\frac{1}{2}}}{\sqrt[3]{\frac{1}{4}}}  )= -\frac{1}{18} and the picture below shows where the answer becomes a negative fraction.

https://www.symbolab.com/solver/logarithms-calculator/%20%5Clog_%7B%5Cfrac%7B1%7D%7B2%7D%5Ccdot%5Cfrac%7B1%7D%7B4%7D%7D%5Cleft(%5Cfrac%7B%5Csqrt%7B%5Cfrac%7B1%7D%7B2%7D%7D%7D%7B%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B4%7D%7D%7D%5Cright)

If you paste that link in your search bar it will give you a even more in depth understanding of how to get this answer

Next is #7, the easier of the two.There are two ways to solve for your answers. According to the graph of this equation there are four possible real solutions. x=2,-2,\sqrt{2}, and -\sqrt{2} . (This does not account for any complex solutions)

Notice that the bases are conjugates which is why the answers are so "nice"

The key is in the exponents

if x^{2} -3 =1 then the sum on the conjugates will be 10 so

x^{2}-3=1
x^{2}=4
so x= 2 or -2

Now for the other two

the solution is also true if x^{2}-3=-1

so

x^{2}-3 = -1\\x^{2}=2\\x=\left \{ {{\sqrt{2}} \atop {-\sqrt{2}}} \right.

the four real solutions are 2, -2, \sqrt{2} ,-\sqrt{2}



6 0
3 years ago
Image attached below. Please help.
goldfiish [28.3K]

Answer:

T,F,T,F,T

Step-by-step explanation:

1. It crosses it there becuase 4(0)-15=-15 for y

2: both top and middle answers are -23, so continuous

3: it increases over that period because the exponent keeps getting bigger

4: No, its not decreasing because -12 plugged in is far less than -23 when -2 is plugged in, meaning its increasing

5: There is no number that would cause an imaginary number or make you divide by zero, meaning all real numbers are fine.

4 0
4 years ago
Please help! I don't understand how to solve this problem
Ilia_Sergeevich [38]

Using the z-distribution, a sample of 142,282 should be taken, which is not practical as it is too large of a sample.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

Assuming an uniform distribution, the standard deviation is given by:

S = \sqrt{\frac{(4 - 0)^2}{12}} = 1.1547

In this problem, we have a 95% confidence level, hence\alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so the critical value is z = 1.96.

The sample size is found solving for n when the margin of error is of M = 0.006, hence:

M = z\frac{\sigma}{\sqrt{n}}

0.006 = 1.96\frac{1.1547}{\sqrt{n}}

0.006\sqrt{n} = 1.96 \times 1.1547

\sqrt{n} = \frac{1.96 \times 1.1547}{0.006}

(\sqrt{n})^2 = \left(\frac{1.96 \times 1.1547}{0.006}\right)^2

n =  142,282.

A sample of 142,282 should be taken, which is not practical as it is too large of a sample.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

8 0
2 years ago
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