In the International Space Station which orbits Earth, astronauts experience apparent weightlessness because:________

When calculating acceleration, what about the answer would tell you that the object is slowing down?

Soloha48 [4]

If the object's velocity and acceleration have <em>opposite signs</em>, then the object is slowing down.

4 0

4 years ago

In a double-slit interference experiment, the slit separation is 2.41 μm, the light wavelength is 512 nm, and the separation bet

Elina [12.6K]

Answer:

Using equation 2dsinФ=n*λ

given d=2.41*10^-6m

λ=512*10^-12m

θ=52.64 degrees

7 0

4 years ago

Read 2 more answers

Suppose we want to calculate the moment of inertia of a 56.5 kg skater, relative to a vertical axis through their center of mass

kirza4 [7]

Answer:

a. 0.342 kg-m² b. 2.0728 kg-m²

Explanation:

a. Since the skater is assumed to be a cylinder, the moment of inertia of a cylinder is I = 1/2MR² where M = mass of cylinder and r = radius of cylinder. Now, here, M = 56.5 kg and r = 0.11 m

I = 1/2MR²

= 1/2 × 56.5 kg × (0.11 m)²

= 0.342 kgm²

So the moment of inertia of the skater is

b. Let the moment of inertia of each arm be I'. So the moment of inertia of each arm relative to the axis through the center of mass is (since they are long rods)

I' = 1/12ml² + mh² where m = mass of arm = 0.05M, l = length of arm = 0.875 m and h = distance of center of mass of the arm from the center of mass of the cylindrical body = R/2 + l/2 = (R + l)/2 = (0.11 m + 0.875 m)/2 = 0.985 m/2 = 0.4925 m

I' = 1/12 × 0.05 × 56.5 kg × (0.875 m)² + 0.05 × 56.5 kg × (0.4925 m)²

= 0.1802 kg-m² + 0.6852 kg-m²

= 0.8654 kg-m²

The total moment of inertia from both arms is thus I'' = 2I' = 1.7308 kg-m².

So, the moment of inertia of the skater with the arms extended is thus I₀ = I + I'' = 0.342 kg-m² + 1.7308 kg-m² = 2.0728 kg-m²

5 0

3 years ago

Figure P2.23 is a somewhat simplified velocity graph for Olympic sprinter Carl Lewis starting a 100 m dash. Estimate his acceler

ehidna [41]

A) Acceleration in part A: $6.1 m/s^2$

B) Acceleration in part B: $2.7 m/s^2$

C) Acceleration in part C: $1.5 m/s^2$

Explanation:

A)

The picture of the problem is missing: find it in attachment.

The acceleration of a body is equal to the rate of change of its velocity:

$a=\frac{v-u}{\Delta t}$

where

v is the final velocity

u is the initial velocity

$\Delta t$ is the time it takes for the velocity to change from u to v

In part A of the race, we have:

u = 0

v = 5.5 m/s (estimate)

$\Delta t = 0.9 - 0 = 0.9 s$

So the acceleration is

$a=\frac{5.5-0}{0.9}=6.1 m/s^2$

B)

In part B of the race, we have:

u = 5.5 m/s is the initial velocity (estimate)

v = 9.5 m/s is the final velocity (estimate)

$\Delta t = 2.4 - 0.9 = 1.5 s$ is the time interval between the two points considered

Therefore, using the equation for the acceleration, we can find the acceleration in part B:

$a=\frac{9.5-5.5}{1.5}=2.7 m/s^2$

C)

In part C of the race, we have:

u = 9.5 m/s is the initial velocity (estimate)

v = 11 m/s is the final velocity (estimate)

$\Delta t = 3.4 - 2.4 = 1 s$ is the time interval between the two points considered

And therefore, the acceleration in part C of the race is:

$a=\frac{11-9.5}{1}=1.5 m/s^2$

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

3 0

3 years ago

1.What is the kinetic energy of an object with a velocity of 7m / s and a mass of 14kg

Vlada [557]

Answer:

Explanation:

The formula for KE is

$KE=\frac{1}{2}mv^2$ and we fill in to solve for KE:

$KE=\frac{1}{2}(14)(7.0)^2$ I used 2 significant digits in the velocity because 1 isn't accurate enough. Therefore, my answer will be rounded to 2 sig fig's:

KE = 340 J (rounded from 343). And we do the exact same thing in #2:

$KE=\frac{1}{2}(5.0)(5.0)^2$ (Used 2sig fig's for both the mass and the velocity) to get

KE = 63 J (rounded from 62.5)

3 0

3 years ago

In the International Space Station which orbits Earth, astronauts experience apparent weightlessness because:_________