Figure P2.23 is a somewhat simplified velocity graph for Olympic sprinter Carl Lewis starting a 100 m dash. Estimate his acceler

Question

3 years ago

6

ation during each of the intervals A, B, and C.

1 answer:

ehidna [41] · Answer 1 · 2022-05-12T01:47:16+03:00

A) Acceleration in part A: $6.1 m/s^2$

B) Acceleration in part B: $2.7 m/s^2$

C) Acceleration in part C: $1.5 m/s^2$

Explanation:

A)

The picture of the problem is missing: find it in attachment.

The acceleration of a body is equal to the rate of change of its velocity:

$a=\frac{v-u}{\Delta t}$

where

v is the final velocity

u is the initial velocity

$\Delta t$ is the time it takes for the velocity to change from u to v

In part A of the race, we have:

u = 0

v = 5.5 m/s (estimate)

$\Delta t = 0.9 - 0 = 0.9 s$

So the acceleration is

$a=\frac{5.5-0}{0.9}=6.1 m/s^2$

B)

In part B of the race, we have:

u = 5.5 m/s is the initial velocity (estimate)

v = 9.5 m/s is the final velocity (estimate)

$\Delta t = 2.4 - 0.9 = 1.5 s$ is the time interval between the two points considered

Therefore, using the equation for the acceleration, we can find the acceleration in part B:

$a=\frac{9.5-5.5}{1.5}=2.7 m/s^2$

C)

In part C of the race, we have:

u = 9.5 m/s is the initial velocity (estimate)

v = 11 m/s is the final velocity (estimate)

$\Delta t = 3.4 - 2.4 = 1 s$ is the time interval between the two points considered

And therefore, the acceleration in part C of the race is:

$a=\frac{11-9.5}{1}=1.5 m/s^2$

Learn more about acceleration:

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