The solution for this problem is computed by through this formula, F = kQq / d²Plugging in the given values above, we can now compute for the answer.
F = 8.98755e9N·m²/C² * -(7e-6C)² / (0.03m)² = -489N, the negative sign denotes attraction.
<h2>
10.5</h2><h3>
remember pemdas</h3>
- parentheses
- exponents <em>excluded for this problem</em>
- multiplication
- division
- addition
- subtraction
<h3>step 1. start with what is at the top of the list.</h3>
<h3>step 2. do 1 times 3 since it comes before division, and is in parentheses.</h3>
1 × 3 = 3
<h3>step 3. find 36 divided by 2</h3>
36 ÷ 2 = 18
<h3>step 4. add the values together</h3>
18 + 3 = 21
<h3>step 5. find 14 times 3</h3>
14 × 3 = 42 <em>you can also do 7 × 6 and will get the same result because 7 is half of 14 and 3 is half of 6</em>
<h3>step 6. add what is outside the parentheses</h3>
21 + 42 = 63
<h3>step 7. divide by 6</h3>
63 ÷ 6 = 10.5
10 remainder of 3 <em>remainder means left over</em>
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It will depend on the frictional force involved in the two. I think it will take more force in sled.
Answer:
if it is a thiner one, yes it will fit because they can expand a pretty far distance
Explanation: