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lisabon 2012 [21]
3 years ago
13

Factor. 10x5−16x4+4x2

Mathematics
2 answers:
Anna11 [10]3 years ago
8 0
The correct answer is 2x^2(5x^3-8x^2+2)
zmey [24]3 years ago
5 0

Answer:

The factor form is \Rightarrow 2x^2(5x^3-8x^2+2)

Step-by-step explanation:

Given: 10x^5-16x^4+4x^2

Factor the polynomial.

First we take common from each term and then factor trinomial

\Rightarrow 10x^5-16x^4+4x^2

10x^5\rightarrow 2x^2\cdot 5x^3

16x^4\rightarrow 2x^2\cdot 8x^2

4x^2\rightarrow 2x^2\cdot 2

So, 2x^2 common from each term and write rest inside the parentheses.

\Rightarrow 2x^2(5x^3-8x^2+2)

Hence, The factor form is \Rightarrow 2x^2(5x^3-8x^2+2)

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If f(x) = 2x^2 + 2, find f(5)
zlopas [31]

Well, following the order of PEMDAS, I got choice B. 52

For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.

Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.

In this case, you square the number 5, which gives you F(5)=2(25)+2

After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.

Finally, you add them, which results in F=52.


By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.

Anyway, hope this helped! :-)  

8 0
3 years ago
1. A box contains 80 tissues. A case contains 24 boxes of tissues and costs
fomenos

Answer:

A .012 cents

Step-by-step explanation:

80 tissues x 24 cases = 1920 tissues in a case

22.56 / 1920 = .01175 (approx .012)

7 0
3 years ago
The sum of two consecutive cube numbers is 341. Work out the two numbers. (2 marks)
Kobotan [32]

Answer:

63 and 53

Step-by-step explanation:

you could use trail and error. So:

13+23=9

33+43=91

63+73=559

53+63=341

3 0
3 years ago
PLEASE ANSWER ASAP WILL GIVE BRAINLY FOR CORRECT ANSWER
omeli [17]

-7(x^2 - 6) + 2y

x = 2 and y= -6

Plug in the numbers and solve

-7(2^2-6) + 2(-6)

-7(4 - 6) + -12

-7(-2) - 12

14 - 12

2

Hope this helps!

3 0
3 years ago
sasha has a riddle: There are two numbers. The sum of the first number and twice the second number is 14.When the second number
N76 [4]

Answer: <u><em>The first no. is 6 and the second no. is 4.</em></u>

Step-by-step explanation: Let the 2 no. s be x and y respectively.

→x+ 2y = 14

<em>→x-y = 2 </em>

<em>∴ x = 2+y</em>

<em>y = y</em>

∴ x+2y=14

= 2+y+2y=14

3y=14-2

3y=12 , y = 12/3=4

∴y = 4

→x = 2+y

= 2+4=6

∴x=6

<u><em>Thus, the first no. is 6 and the second no. is 4.</em></u>

5 0
3 years ago
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