3 years ago

In a right triangle, the value of cos B = 3/5. What is the value of sin B?

Mathematics

1 answer:

ozzi3 years ago

7 0

Answer:

4/5

Step-by-step explanation:

cos B = 3/5

cos Ф = adjacent/hypothesis

hypothesis ² = adjacent² + opposite²

5²= 3²+ o²

25 = 9+o²

25-9=o²

16 = o²

√16 = o = 4

Sin B = opposite/hypothesis = 4/5

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