Question

Find the value of x for which the graph of y = 3x^2 - 8x + 7 achieves its minimum y-value.​

Answer 1

Answer:

The y value achieves its minimum at x = 4/3

Step-by-step explanation:

Given the graph of y to be 3x² - 8x + 7, to get the value of x for which the graph function achieves its minimum y value, we need to find its turning point first.

At the turning point, dy/dx = 0

Given y = 3x² - 8x + 7

$\frac{dy}{dx} = 6x-8\\ at\ turning\ point\ 6x-8 = 0$

$6x = 8\\x = \frac{8}{6}\\ x =\frac{4}{3}$

The y value achieves its minimum at x = 4/3