Find the value of x for which the graph of y = 3x^2 - 8x + 7 achieves its minimum y-value.
1 answer:
Answer:
<h3>The y value achieves its minimum at x = 4/3</h3>Step-by-step explanation:
Given the graph of y to be 3x² - 8x + 7, to get the value of x for which the graph function achieves its minimum y value, we need to find its turning point first.
At the turning point, dy/dx = 0
Given y = 3x² - 8x + 7
The y value achieves its minimum at x = 4/3
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Answer:
3x +8y = -17
Step-by-step explanation:
The point-slope equation is a good place to start.
y -k = m(x -h) . . . . . equation through (h, k) with slope m
Filling in your numbers gives ...
y +4 = -3/8(x -5)
Multiplying by 8, we get
8y + 32 = -3x + 15
Adding 3x-32 puts this in standard form.
3x + 8y = -17
_____
Standard form is ...
ax +by = c
where a, b, c are mutually-prime integers and the leading coefficient is positive. (If a=0, the leading coefficient is b.)
