Make c the subject: x=-b+(b²-4ac) divided by 2a The brackets mean square root

1 answer:

7 0

$x=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\
2ax=-b+\sqrt{b^2-4ac}\\
\sqrt{b^2-4ac}=2ax+b\\
b^2-4ac=(2ax+b)^2\\
-4ac=4a^2x^2+4abx+b^2-b^2\\
-4ac=4a^2x^2+4abx\\
c=-ax^2-bx$

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