V = 38.55 mL - 15.75 mL = 22.80 mL = 22.80 cm³
D =
![\frac{M}{V}](https://tex.z-dn.net/?f=%20%5Cfrac%7BM%7D%7BV%7D%20)
=
![\frac{31.745 g}{ 22.80 cm^{3} }](https://tex.z-dn.net/?f=%20%5Cfrac%7B31.745%20g%7D%7B%2022.80%20cm%5E%7B3%7D%20%7D%20)
= 1.392 g/cm³
Answer:
Carbon and Oxygen cannot react to form an ionic compound because the two elements are non-metals. To form an ionic bond, a metal combines with a non-metal through electrostatic attraction of oppositely charged ions.
Answer:
The appropriate answer is "342 g/mol".
Explanation:
Given:
Freezing point,
= 0.93°C
Kf,
= 1.86°C/m
Mass,
= 171
As we know,
⇒ ![Freezing \ point = Kf\times molality](https://tex.z-dn.net/?f=Freezing%20%5C%20point%20%3D%20Kf%5Ctimes%20molality)
![0.93=1.86\times molality](https://tex.z-dn.net/?f=0.93%3D1.86%5Ctimes%20molality)
![Molality=\frac{0.93}{1.86}](https://tex.z-dn.net/?f=Molality%3D%5Cfrac%7B0.93%7D%7B1.86%7D)
![=0.5 \ m](https://tex.z-dn.net/?f=%3D0.5%20%5C%20m)
Now,
⇒ ![Molality=\frac{moles \ of \ sugar}{mass \ of \ water}](https://tex.z-dn.net/?f=Molality%3D%5Cfrac%7Bmoles%20%5C%20of%20%5C%20sugar%7D%7Bmass%20%5C%20of%20%5C%20water%7D)
![moles \ of \ sugar=0.0005 \ mol](https://tex.z-dn.net/?f=moles%20%5C%20of%20%5C%20sugar%3D0.0005%20%5C%20mol)
hence,
The molar mass of the sugar will be:
= ![\frac{mass}{moles}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmoles%7D)
= ![\frac{171\times 10^{-3}}{0.0005}](https://tex.z-dn.net/?f=%5Cfrac%7B171%5Ctimes%2010%5E%7B-3%7D%7D%7B0.0005%7D)
= ![342 \ g/mol](https://tex.z-dn.net/?f=342%20%5C%20g%2Fmol)
Answer:
V3− B) A nonmetal that gained three electrons
X− A) A nonmetal that gained one electron
Y+ C) A metal that lost one electron
Z3+ D) A metal that lost three electrons
Explanation:
As per the Octet rule, each atom must have eight electrons in its outermost shell.
The non-metals gain electrons while reacting to reach the configurations of noble gas as they possess lower Ionization ability and higher electro-negativity. Thus, they will have a negative charge(V3 -, X-)
Metals, on the other hand, lose electrons to reach a stable octet configuration due to the higher electro-positivity and lower electron affinity. Therefore, they will have a positive charge(Y+, Z3+).