Answer:
c. 0.750 atm .
Explanation:
Hello!
In this case, since the two vessels have different volume, we can see that the gas is initially at 3.00 atm into the 1.00-L vessel, but next, it is allowed to move towards the 3.00-L vessel, meaning that the final volume wherein the gas is located, is 4.00 L; therefore, we use the Boyle's law to compute the final pressure:
Therefore the answer is c. 0.750 atm .
Best regards!
Answer : The reaction rate will be,
Explanation :
Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.
For the given chemical equation:
Rate law expression for the reaction:
where,
a = order with respect to
b = order with respect to
Expression for rate law for first observation:
....(1)
Expression for rate law for second observation:
....(2)
Expression for rate law for third observation:
....(3)
Expression for rate law for fourth observation:
....(4)
Dividing 1 from 2, we get:
Dividing 3 from 2, we get:
Thus, the rate law becomes:
Now, calculating the value of 'k' by using any expression.
Putting values in above rate law, we get:
Now we have to determine the reaction rate when the concentration of is 0.135 M and that of
is 0.40 M.
Therefore, the reaction rate will be,