Answer:
77.98 g/mol ≅ 78.0 g/mol.
Explanation:
- The molar mass of any compound can be calculated by the sum of the atomic masses of different atoms in the compound multiplied by its no. in the compound.
Molar mass of Al(OH)₃ = (Atomic mass of Al) + 3(Atomic mass of O) + 3(Atomic mass of H)
Atomic mass of Al = 26.98 g/mol. & Atomic mass of O = 16.0 g/mol & Atomic mass of H = 1.0 g/mol.
<em>∴ Molar mass of Al(OH)₃</em> = (26.98 g/mol) + 3(16.0 g/mol) + 3(1.0 g/mol) = <em>77.98 g/mol ≅ 78.0 g/mol.</em>
The oxidation number of Chlorine in NaClO4 is +7. It can also be estimated by counting the # of bonds to Chlorine.
The maximum number is 10 electrons
Types of Bonds can be predicted by calculating the
difference in electronegativity.
If, Electronegativity difference is,
Less
than 0.4 then it is Non Polar Covalent Bond
Between 0.4 and 1.7 then it is Polar Covalent Bond
Greater than 1.7 then it is Ionic
For N and Se,
E.N of Nitrogen = 3.04
E.N of Selenium = 2.55
________
E.N Difference
0.49 (Weakly Polar Covalent)
As you have not provided remaining pairs, so if you have any of them, follow the method as mentioned above.
For the answer to the question above,
in this problem we can use the concept of freezing point depression since we are given the freezing point of the solution.
ΔT = -k(f) x m x i
-2.24 - 0 = -1.86 x m x 3
<span>m = 0.4014
</span>So the answer to your question is m = 0.4014