Find the product. Simplify your answer. (4z–1)(z–3)
1 answer:
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The four consecutive terms are 2,6,10,14.
Explanation:
Let the four consecutive terms of an arithmetic progression be (a - 3d), (a - d),(a + d), (a + 3d)
It is given that the sum of four consecutive terms is 32.
Thus, adding all the four consecutive terms, we have,
Thus, the value of a is 8.
It is also given that the ratio of the product of first and last term to the product of the two middle terms is 7:15. Thud, we have,
Simplifying the terms, we have,
Now, substituting a = 8, we have,
Thus, the value of d is 2.
Now, we shall substitute the value of a and d in the terms (a - 3d), (a - d),(a + d), (a + 3d), we get, the four consecutive terms.
Thus, the four consecutive terms are 2,6,10,14.