Answer:
B
Step-by-step explanation:
The equation is (2x+5)^2.
It can't be A because 2 is the multiplier for only x.
It can't be C because the square is outside of the equation.
It can't be D because again, the square is outside of the equation.
So the only thing left is B.
Hope this helped!


- <u>The </u><u>sum</u><u> </u><u>of </u><u>the </u><u>number </u><u>in </u><u>each </u><u>of </u><u>the </u><u>four </u><u>rows </u><u>is </u><u>the </u><u>same </u>
- <u>The </u><u>sum </u><u>of </u><u>the </u><u>numbers </u><u>in </u><u>each </u><u>of </u><u>the </u><u>three </u><u>columns </u><u>is </u><u>the </u><u>same</u>
- <u>The </u><u>sum </u><u>of </u><u>any </u><u>row </u><u>does </u><u>not </u><u>equal </u><u>the </u><u>sum </u><u>of </u><u>any </u><u>column </u>

<u>According </u><u>to </u><u>the </u><u>Second</u><u> </u><u>rule </u><u>:</u><u>-</u>


<u>According </u><u>to </u><u>the </u><u>first </u><u>rule </u><u>:</u><u>-</u><u> </u>


<u>From </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u> </u><u>we </u><u>got </u><u>:</u><u>-</u>



<u>Subsitute </u><u>(</u><u>3</u><u>)</u><u> </u><u>in </u><u>(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>:</u><u>-</u>


<u>We</u><u> </u><u>can </u><u>write </u><u>it </u><u>as </u><u>:</u><u>-</u>



<u>Subsitute </u><u>the </u><u>value </u><u>of </u><u>c </u><u>and </u><u>e </u><u>in </u><u>(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>


<u>Now</u><u>, </u>









Hence, The value of a, b, c, d and e is 23, 31 ,60 ,33 and 51 .
Answer:
(19.6,-12)
Step-by-step explanation:
Answer:
A)4.6 yard
Step-by-step explanation:
![x^{2} +10^{2} =11^{2} \\x^{2} =21\\x=\sqrt[2]{21} \\](https://tex.z-dn.net/?f=x%5E%7B2%7D%20%2B10%5E%7B2%7D%20%3D11%5E%7B2%7D%20%5C%5Cx%5E%7B2%7D%20%3D21%5C%5Cx%3D%5Csqrt%5B2%5D%7B21%7D%20%5C%5C)
x≅4.6
Hoped I helped, have a nice day!