Answer:
the answer is descriptive
Explanation:
descriotive never ever have hypothisis
Answer:
Explanation:
The reaction is:
C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
We see, that the equation is ballanced.
As we have data from only one reactant, we assume the other is in excess.
Ratio is 1:4 (stoichiometry). We solve this, by a rule of three:
1 mol of propane can produce 4 moles of water
Then, 4 moles of propane, may produce
( 4 . 4 ) /1 = 16 moles of water can be made.
Remember, we always have to work with the limiting reactant.
Answer:
1. Dmitri Mendeleev
2. Johann Dobhereiner
3. John Newlands
4. Henry Moseley
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Answer:
pH = 8.477
Explanation:
∴ ni 0.3 - -
nf - 0.3 0.3
∴ ni 0.50 - 0.3
nf 0.5 - X X 0.3 + X
∴ Ka = 2.0 E-9 = ([H3O+]*[OBr-]) / [HOBr]
⇒ Ka = 2.0 E-9 = ((X/1L)*(0.3 + X)/1 L) / ((0.5 - X)/1L)
⇒ 2.0 E-9 = ( 0.3X + X² ) / (0.5 - X)
⇒ X² + 0.3X - 1 E-9 = 0
⇒ X = 4.333 E-9 M
according Henderson-Hauselbach:
- pH = pk + Log [A-] / [HA]
∴ [OBr-] = 0.3 mol/ 1 L + 4.333 E-9 M = 0.300 M
∴ [HOBr] = 0.5 mol / 1 L - 4.33 E-9 M = 0.500 M
∴ pKa = - log Ka = - Log ( 2.0 E-9 ) = 8.6989
⇒ pH = 8.6989 + Log ( 0.300/0.500 )
⇒ pH = 8.477