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grandymaker [24]
3 years ago
9

Identify the law that explains the following observation:

Chemistry
1 answer:
kirill [66]3 years ago
4 0

Answer:

Proust's law of definite proportion

Explanation:

The law of constant proportion states that the components elements of a given chemical compound combine with each other in a fixed mass ratio when the compound is produced by any given process

Therefore, from the question, the chemical formula for Nitrogen Dioxide is NO₂, where the molar mass of nitrogen, N = 14

The molar mass of oxygen, O = 16

Given that one molecule of NO₂, contains one atom of nitrogen and two atoms of oxygen, one mole of NO₂ will contain 14 grams of nitrogen and 32 grams of oxygen, according to Proust's law of definite proportion.

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A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spheric
Luba_88 [7]

Complete Question

A marine biologist is preparing a deep-sea submersible for a dive. The sub stores breathing air under high pressure in a spherical air tank that measures 74.0 wide. The biologist estimates she will need 2600 L of air for the dive. Calculate the pressure to which this volume of air must be compressed in order to fit into the air tank. Write your answer in atmospheres. Round your answer to significant digits.

Answer:

The pressure required is P_2= 12.2 \ atm

Explanation:

Generally the volume of a sphere is mathematically denoted as

             V_s = \frac{4}{3} * \pi r^3

Substituting r =  \frac{d}{2} = \frac{74}{2} = 37cm

          V_s = \frac{4}{3} * 3.42 * (37)^2

               V_s = 2.121746 *10^5 cm^3

Converting to Liters

               V_s = \frac{2.121746 *10^5}{1000}

                V_s= 212.1746L

Assume that the pressure at which the air is given to the diver is 1 atm when the air was occupying a volume of 2600L

So

From Charles law

               P_1V_1 = P_2 V_s

Substituting  V_1 =2600 L ,   P_1 = 1 atm , V_s  =212.1746L , and making P_2 the subject we have

                 P_2 = \frac{P_1 * V_1}{V_s}

                     = \frac{1 * 2600}{212.1746}

                    P_2= 12.2 atm

               

6 0
3 years ago
What is the ph of a 0.15 m solution of ammonium chloride?
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 Best Answer:  <span>(a) 
8.9 x 10^-7 = x^2 / 0.15-x 
x = [OH-] = 0.00037 M 
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(b) 
Ka = Kw/Kb = 5.6 x 10^-10 = x^2 / 0.20-x 
x = [H+] = 0.000011 M 
pH = 5.0</span>
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