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3 years ago

What is the molas mass of lithium oxide li2o

Chemistry

2 answers:

gladu [14]3 years ago

7 0

The molar mass of lithium oxide is
29.88 g/mol

Alexxandr [17]3 years ago

6 0

Explanation:

Atomic mass means the sum of total number of protons and neutrons present in an element.

Molar mass is defined as the mass of one mole of a compound present in grams.

For example, molar mass of $Li_{2}O$ is as follows.

Molar mass of $Li_{2}O$ = 2 × atomic mass of Li + atomic mass of O

= $2 \times 6.94 g/mol + 16.0 g/mol$

= 13.88 g/mol + 16.0 g/mol

= 29.88 g/mol

Thus, we can conclude that molar mass of $Li_{2}O$ is 29.88 g/mol.

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Answer:

a) $T_{2} = 360.955\,K$ , $P_{2} = 138569.171\,Pa\,(1.386\,bar)$ , b) $T_{2} = 347.348\,K$ , $V_{2} = 0.14\,m^{3}$

Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

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$P_{2} = \frac{T_{2}}{T_{1}}\cdot P_{1}$

$P_{2} = \frac{360.955\,K}{298\,K}\cdot \left(101,325\,Pa + \frac{(200\,kg)\cdot (9.807\,\frac{m}{s^{2}} )}{0.15\,m^{2}}\right)$

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$\frac{T_{1}}{V_{1}} = \frac{T_{2}}{V_{2}}$

Final temperature is cleared from this expression:

$Q = n\cdot \bar c_{p}\cdot (T_{2}-T_{1})$

$T_{2} = T_{1} + \frac{Q}{n\cdot \bar c_{p}}$

$T_{2} = 298\,K +\frac{10,500\,J}{(5.541\,mol)\cdot (38.4\,\frac{J}{mol\cdot K} )}$

$T_{2} = 347.348\,K$

The final volume is:

$V_{2} = \frac{T_{2}}{T_{1}}\cdot V_{1}$

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