I think it’s a or b but I would wait until someone else answer
3.8mL of 0.42 phosphoric acid is required.
Reaction
2H3PO4 + 3CaCL3 → Ca3(PO)4 + 6HCl
moles CaCl2 =0.16 mol/L x0.010 L = 0.0016 mol
moles of H3Po4
= 0.0016mol of CaCl2 x 2 mole of H3PO4/3mole of CaCl2
= 0.00106 mol
V of H3PO4 = 0.0016/0.42 = 0.0038L = 3.8mL
V of H3PO4=3.8mL
To know more about calculation in milliliters refer to:-
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Answer:
Freezing points for water with freezing mixtures based on salt and ice: Ammonium Nitrate - Chrushed Ice or Snow in Water 1 part Ammonium Nitrate - 0.94 parts Ice/water : temperature -4 o C 1 part Ammonium Nitrate - 1.20 parts Ice/water : temperature -14 o C
Explanation:
144 calories worth, this is not a joke.
Answer:
Explanation:
Each magnesium atom loses two electrons and each iodine atom gains one electron. So there should be a 1-to-2 ratio of magnesium ions to iodide ions.