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3 years ago

Someone talk to me , don't just say hi and then leave

Chemistry

2 answers:

Oliga [24]3 years ago

8 0

shhdjrrjhfjfjvnfjdjsjsjsjs

Bogdan [553]3 years ago

5 0

Answer:

1. I like to be named by my nickname which is Kiki, I'm 17 and a Female.

2. I love basketball, orange and blue cuz I can't choose, and spicy chicken nuggets.

3. We can be friends but I don't talk a lot.

4. I have just two brothers.

5. I'm very clumsy but I never have broken a bone nor had surgery but I had to go to the hospital many times.

There you go :)

You might be interested in

In their notebook you see that it takes 9 hours for a sixth of a 0.5M solution of BC2 to react. Unfortunately, you have somewher

trasher [3.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The concentration of $BC_2$ that should used originally is $C_Z_o = 0.4492M$

Explanation:

From the question we are told that

The necessary elementary step is

$2BC_2 ----->4C + B_2$

The time taken for sixth of 0.5 M of reactant to react $t = 9 hr$

The time available is $t_a = 3.5 hr$

The desired concentration to remain $C = 0.42M$

Let Z be the reactant , Y be the first product and X the second product

Generally the elementary rate law is mathematically as

$-r_Z = kC_Z^2 = - \frac{d C_Z}{dt}$

Where k is the rate constant , $C_Z$ is the concentration of Z

From the elementary rate law we see that the reaction is second order (This because the concentration of the reactant is raised to power 2 )

For second order reaction

$\frac{1}{C_Z} - \frac{1}{C_Z_o} = kt$

Where $C_Z_o$ is the initial concentration of Z which a value of $C_Z_o = 0.5M$

From the question we are told that it take 9 hours for the concentration of the reactant to become

$C_Z = C_Z_o - \frac{1}{6} C_Z_o$

$C_Z = 0.5 - \frac{0.5}{6}$

$= 0.4167 M$

$\frac{1}{0.4167} - \frac{1}{0.50} = 9 k$

$0.400 = 9 k$

=> $k = 0.044\ L/ mol \cdot hr^{-1}$

For $C_Z = 0.42M$

$\frac{1}{0.42} - \frac{1}{C_Z_o} = 3.5 * 0.044$

$2.38 - 0.154 = \frac{1}{C_Z_o}$

$2.226 = \frac{1}{C_Z_o}$

$C_Z_o = \frac{1}{2.226}$

$C_Z_o = 0.4492M$

4 0

3 years ago

How many pi bonds are present in a molecule of HCP?

Anestetic [448]

Answer:

Explanation:

6 0

3 years ago

A 1.85 kg textbook is sitting on a bookshelf 2.23 m above the floor. How much potential energy does it have?

neonofarm [45]

Answer:

$\boxed {\boxed {\sf 40.4299 \ Joules}}$

Explanation:

Potential energy is energy due to position. It is the product of mass, height, and acceleration due to gravity.

$PE= m \times g \times h$

The mass of the textbook is 1.85 kilograms. Assuming this is on Earth, the acceleration due to gravity is 9.8 meters per square second. The height is 2.23 meters.

m= 1.85 kg
g= 9.8 m/s²
h= 2.23 m

Substitute the values into the formula.

$PE = 1.85 \ kg \times 9.8 \ m/s^2 \times 2.23 \ m$

Multiply the first 2 numbers together.

$PE=18.13 \ kg*m/s^2 *2.23 \ m$

Multiply again.

$PE= 40.4299 \ kg*m^2/s^2$

1 kilogram square meter per square second (1 kg*m²/s²) is equal to 1 Joules (J)
Our answer of 40.4299 kg*m²/s² is equal to 40.4299 J

$PE= 40.4299 \ J$

The textbook has <u>40.4299 Joules of potential energy.</u>

7 0

3 years ago

A mixture of two gases has a total pressure of 5.7 atm . If one gas has a partial pressure of 4.1 atm , what if the partial pres

Mrrafil [7]

If the two gases has a total pressure of 5.7 atm and one of the gases has a partial pressure of 4.1 the the other one has the pressure of 1.6

6 0

3 years ago

Read 2 more answers

25 POINTS:)

Digiron [165]

I suppose that the answer is A

6 0

3 years ago