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Westkost [7]
3 years ago
11

If CD has endpoints (–3, 4) and (5, 2), what are the coordinates of its midpoint?

Mathematics
1 answer:
Aleks [24]3 years ago
5 0
You can read it of the graph which is (1,3) or also calculate it with vectors:

calculate the vector CD:
(5-(-3),2-4)=(8,-2)
to calculate the midpoint you need half of the vector length:
(8,-2)/2=(4,-1)
add the vector to C:
(-3,4)+(4,-1)=(1,3)=midpoint of CD

so it's the third option
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(w + 3) + w ≥ 15 in


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3 years ago
A rhombus and a square have one and the same side of 6 cm. The area of the rhombus is 4/5 of the area of the square. Find the he
Arada [10]
You will find the area the square and then find out what 4/5 of that area is.

A = bh
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The area of the rhombus is 28 4/5 square cm.  Use this to solve for the height of the rhombus.

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The height of the rhombus is 4 4/5 cm.
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Generate the nest three terms of each arithmetic sequence shown below.
o-na [289]

Answer:

A)2,6,10

B)2,-6,-18

C)-1,-3,-5

Step-by-step explanation:

<u>A)a1=-2 and d=4</u>

We know that the arithmetic sequence formula is

a_{n}=a_{1}+(n-1)d

Now

a_{2}=a_{1}+(2-1)d

a_{2}=a_{1}+(1)d

Substituting the given value we get

a_{2}= -2+(1)4

a_{2}= -2+4

a_{2}= 2

------------------------------------------

Similarly

a_{3}=a_{1}+(3-1)d

a_{3}=a_{1}+(2)d

Substituting the given value we get

a_{3}= -2+(2)4

a_{3}= -2+8

a_{3}= 6

-------------------------------------------------

a_{4}=a_{1}+(4-1)d

a_{4}=a_{1}+(3)d

Substituting the given value we get

a_{4}= -2+(3)4

a_{4}= -2+16

a_{4}= 10

-------------------------------------------------------------------------------------------

<u>B</u><u>  a_n=a_{(n-1)}-8  with a_1=10</u>

a_2=a_{(2-1)}-8

a_2=a_{1}-8

Substituting the given value

a_2= 10-8

a_2=2

---------------------------------------------------------------------

a_3=a_{(3-1)}-8

a_3=a_{2}-8

Substituting the  value

a_3=2-8

a_3= -6

---------------------------------------------------------------------

a_4=a_{(4-1)}-8

a_4=a_{3}-8

Substituting the  value

a_4= -6-8

a_4= -14

-------------------------------------------------------------------------------------------

<u>C) a_1=3, a_2=1</u>

Here the difference is -2

the arithmetic sequence formula is

a_{n}=a_{1}+(n-1)d

Now

a_{3}=a_{1}+(3-1)d

a_{3}=a_{1}+(2)d

Substituting the value we get

a_{3}= 3+(2)-2

a_{3}= 3-4

a_{3}= -1

------------------------------------------------------------------------------

a_{4}=a_{1}+(4-1)d

a_{4}=a_{1}+(3)d

Substituting the value we get

a_{4}= 3+(3)-2

a_{4}= 3-6

a_{4}= -3

----------------------------------------------------------------------------------

a_{5}=a_{1}+(5-1)d

a_{5}=a_{1}+(4)d

Substituting the value we get

a_{5}= 3+(4)-2

a_{5}= 3-8

a_{5}= -5

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3 years ago
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