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enyata [817]
3 years ago
12

Examine the peptide. Thr‑Glu‑Pro‑Ile‑Val‑Ala‑Pro‑Met‑Glu‑Tyr‑Gly‑Lys Thr‑Glu‑Pro‑Ile‑Val‑Ala‑Pro‑Met‑Glu‑Tyr‑Gly‑Lys Write the s

equence using one‑letter abbreviations.
Chemistry
1 answer:
KonstantinChe [14]3 years ago
5 0

Answer:

The answer to your question is    T-E-P-I-V-A-P-M-E-Y-G-K

Explanation:

Thr   T           Threonine

Glu   E           Glutamate

Pro   P            Proline

Ile     I             Isoleucine

Val    V           Valine

Ala   A             Alanine

Pro   P             Proline

Met  M            Methionine

Glu   E             Glutamate

Tyr    Y            Tyrosine

Gly   G             Glycine

Lys    K             Lysine

Final sequence:  T-E-P-I-V-A-P-M-E-Y-G-K

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An element is to a __ as an organ is to a ___
Vera_Pavlovna [14]

Answer:

An element is to a compound as an organ is to tissue

Explanation:

5 0
3 years ago
Sulfur dioxide and oxygen react to form sulfur trioxide during one of the key steps in sulfuric acid synthesis. An industrial ch
Salsk061 [2.6K]

Answer:

kp= 3.1 x 10^(-2)

Explanation:

To solve this problem we have to write down the reaction and use the ICE table for pressures:

                                2SO2      +        O2         ⇄              2SO3

Initial                      3.4 atm           1.3 atm                         0 atm

Change                    -2x                    - x                                + 2x

Equilibrium            3.4 - 2x            1.3 -x                          0.52 atm

In order to know the x value:

2x = 0.52

x=(0.52)/2= 0.26

                               2SO2             +          O2              ⇄              2SO3

Equilibrium        3.4 - 0.52                1.3 - 0.26                     0.52 atm

Equilibrium        2.88 atm                 1.04 atm                      0.52 atm

with the partial pressure in the equilibrium, we can obtain Kp.

Kp=\frac{PSO3^2}{PSO2^2 PO2}=\frac{(0.52)^2}{(2.88)^2(1.04)}=0.03135

8 0
3 years ago
You will need to prepare 12 mL of 25% Sodium Phosphate Buffer (pH 4) solution for Activity 2. What volume of the stock Sodium Ph
zhuklara [117]

Assuming the concentration of stock solution is 50% sodium phosphate buffer solution, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.

<h3>What volume of a stock Sodium phosphate buffer and water is needed to 12 mL of 25% sodium phosphate buffer of pH 4?</h3>

The process of preparing solutions from stock solutions of higher concentration is known as dilution.

Dilution is done with the aid of the dilution formula given below:

  • C1V1 = C2V2

where

  • C1 is the concentration of stock solution
  • V1 is the volume of stock solution required to prepare a diluted solution
  • C2 is the concentration of the diluted solution prepared
  • V2 is the final volume of the diluted solution

From the data provided:

C1 is not given

V1 is unknown

C2 = 25%

V2 = 12 mL

  • Assuming C1 is 50% solution

Volume of stock, V1, required is calculated as follows:

V1 = C2V2/C1

V1 = 25 × 12 /50

V1 = 6 mL

Therefore, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.

Learn more about dilution formula at: brainly.com/question/7208546

6 0
2 years ago
Why do we think mercury has so many tremendous cliffs?
wlad13 [49]

Answer:

it is sticky

Explanation:

hope it helps

4 0
2 years ago
Read 2 more answers
I NEED HELP ASAP DON'T JUST ANSWER FOR POINTS OR YOU WILL GET REPORTED!
White raven [17]

Answer:

The number of neutrons is entirely dependent on the Mass number of the particular atom. The standard mass for potassium is 39.

Potassium is element number 19, so it has 19 protons and 19 electrons in the neutral atom. It has therefore 39-19 = 20 Neutrons.

Explanation:

7 0
3 years ago
Read 2 more answers
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