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3 years ago

Which of these is an example of a chemical change?

Chemistry

2 answers:

svlad2 [7]3 years ago

8 0

Feeling ice melt on your skin

Dominik [7]3 years ago

7 0

No a chemical change is when the actual thing changes, it would be the last one because there is a chemical reaction as the sheets get moldy

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Prepare a 0.50 L of a 1.0 M solution of potassium sulfate. Determine the amount of potassium sulfate needed in correct significa

Lera25 [3.4K]

Answer:

B) 87g

Explanation:

Usatestprep said it

3 0

3 years ago

Un medicamento corresponde a una disolución de "nafazolina" (sustancia activa) en agua purificada, en una concentración de 12% V

ratelena [41]

Answer:

12 mL

Explanation:

Según la pregunta;

V / V% concentración del fármaco = 12%

volumen de la solución = 100 ml

De;

V / V% = volumen de fármaco / volumen de solución

volumen de fármaco = V / V% × volumen de solución

volumen de fármaco = 12/100 × 100

= 12 mL

5 0

3 years ago

A.it is physical change

PIT_PIT [208]

A physical change is when something don't permanently change

5 0

3 years ago

What are the charges and relative masses of the 3 main subatomic particles

blondinia [14]

Proton: positive- mass equal to neutron
Electron: negative- mass 1/1840 mass of proton
Neutron: no charge- same mass as proton

5 0

3 years ago

At a given temperature, 4.06 atm of H2 and 3.5 atm of Cl2 are mixed and allowed to come to equilibrium. The equilibrium pressure

Llana [10]

<u>Answer:</u> The value of $K_p$ for the given chemical reaction is 0.1415

<u>Explanation:</u>

Equilibrium constant in terms of partial pressure is defined as the ratio of partial pressures of the products and the reactants each raised to the power their stoichiometric ratios. It is expressed as $K_p$

For a general chemical reaction:

$aA+bB\rightarrow cC+dD$

The expression for $K_p$ is written as:

$K_p=\frac{p_{C}^cp_{D}^d}{p_{A}^ap_{B}^b}$

For the given chemical equation:

$H_2(g)+Cl_2(g)\rightleftharpoons 2HCl(g)$

The expression for $K_p$ for the following equation is:

$K_p=\frac{(p_{HCl})^2}{(p_{H_2)}(p_{Cl_2})}$

We are given:

$p_{HCl}=1.418atm\\p_{H_2}=4.06atm\\p_{Cl_2}=3.5atm$

Putting values in above equation, we get:

$K_p=\frac{(1.418)^2}{(4.06)\times (3.5)}\\\\K_p=0.1415$

The value of $K_p$ for the given chemical reaction is 0.1415

5 0

3 years ago