They occur in patterns because certain features are formed at the site of the three types of plate boundaries.
Answer:
12.19 hours prior to discovery was the corpse placed in the desert.
Explanation:
Heat required for fly eggs to develop into first instar larvae = 
From the given,
Exposure time = 16 hrs
Temperature = 27 C
The day time exposed hours is 10 hrs.-(7.00am-5.00pm)
So, the extra heat = 427.2-378= 49.2
The addition heat divided by average temperature.
Average temperature = 22.4 C
So, the total time exposed is night time hours to day time hours.
= 10+2.19 = 12.19 hrs.
Therefore, 12.19 hours prior to discovery was the corpse placed in the desert.
Answer:
301.8 g
Explanation:
We prepare a solution with 200.4 g of water (solvent) and 101.42 g of salt (solute). The mass of the solution is equal to the sum of the mass of the solvent and the mass of the solute.
m(solution) = m(solute) + m(solvent)
m(solution) = 200.4 g + 101.42 g
m(solution) = 301.8 g (we round-off to one decimal according to the significant figures rules)
Answer:
0.08 mol L-1
Explanation:
Sulfuric acid Formula: H2SO4
Ammonia Formula: NH3
Ammonium sulfate Formula: (NH₄)₂SO₄
H2SO4 + 2NH3 = 2NH4+ + SO4 2-
H2SO4 + 2NH3 = (NH₄)₂SO₄
H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L
= 0.08 mol L-1
Answer:
The correct answer is D
<u>18.016 g</u>
<u></u>
Explanation:
Molecular Weight : It is the sum of atomic weights of each atoms present in the compound.
The molecular weught is measured in atomic mass.unit( amu) or simply"u"
This is calculated by using :
Molecular weight = number of atom x atomic mass of the atom
For H2O
Number of H atoms = 2
Number of O atom = 1
Molecular weight of H2O = 2(mass of H atom) + 1(mass of O atom)
Molecular weight = 2(1.00784) + 15.999
= 18.01558 u
= 18.016 u
