The correct answer is option D. i.e. <span>pressure, temperature, or concentration.
Equilibrium reactions can involve
1) changes in the temperature conditions - high or low or exothermic or endothermic.
2) Pressure - By increasing or decreasing the pressure
3) Concentration - the changes in concentration take place in either products side or reactants side.
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The ionic equation will be:
<span>Mg2+(aq) + 2OH-(aq) + 2H+(aq) + 2NO3-(aq) → Mg2+(aq) + 2NO3-(aq) + 2H2O(l)
</span>And the net ionic:
<span>2OH-(aq) + 2H+(aq) → 2H2O(l)
</span>a Balanced equation would be:
<span>Mg(OH)2(aq) + 2HNO3(aq) → Mg(NO3)2 (aq) + 2H2O(l)
</span>Now thsi si so because of the standard equation which is base plus acid=Salt plus water. We need to have in mindo that Mg(OH)2 is sparingly soluble in water and is aqueous mos of the times
Answer:
Neither side is favored
Explanation:
In a reaction at equilibrium in which reactants and products are gases, pressure is a factor that produces a shift of the equilibrium position. When the pressure is increased, the equilibrium is shifted to the side of the reaction with a fewer moles. In this reaction:
2 HD(g) ⇀↽ H₂(g) + D₂(g)
There is the same number of moles on both sides:
reactants side: 2 moles HD
products side: 1 mol H₂ + 1 mol D₂ = 2 moles
Therefore, the equilibrium position will not change.
Because the decomposition is the reverse process of the formation.
Enthalpy is a function of state, which means that the value dependes only on the state and not the pathway.
Then the change of enthalpy is the same in magnitude for both cases but in formation the change is netavie (releases energy) and in the other is postive (absorbs energy).
Answer:
a i think i hope this hepls
Explanation: