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Nikolay [14]
4 years ago
14

Advertising claims sometimes state that adding something mechanical to a car's engine will allow it to recover 100 percent of th

e energy that comes from burning gasoline. You should be skeptical of such claims because they violate the
A. first law of thermodynamics.
B. activation energy requirements of all chemical reactions.
C. second law of thermodynamics.D. law of conservation of matter
Chemistry
1 answer:
Elan Coil [88]4 years ago
4 0

Answer:

second law of thermodynamics.

Explanation:

The second law of thermodynamics deals with interconversion of energy from one form to another. Although energy can be converted from one form to another, this conversion is never 100% efficient because energy is lost in certain ways such as through heat. In a combustion engine, it is not possible to recover the energy from the gasoline 100% since energy must be lost along the way via such means as heat losses. Hence I will be skeptical about such an advert.

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Each are non-metals, which form a covalent bond. They also have high electron rapport.
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5 0
3 years ago
New industrial plants for acetic acid react liquid methanol (Mm=32g/m) with carbon monoxide in the presen of a catalyst. In an e
Daniel [21]

Answer:

21.42 g

Explanation:

To know this, you need to put the equation that is taking and it's the following:

CH3OH (Methanol) + CO ---------> CH3COOH (Acetic acid)

We already know the mm of methanol, and the mm for CO is:

AM of C = 12 g/mol

AM of O = 16 g/mol

AM of H = 1 g/mol

MM of CO = 12 + 16 = 28 g/m

For acetic acid: 12 + 3(1) + 12 + 16*2 + 1 = 60 g/mol

Now that we know the molar mass of each molecule, let's calculate the number of moles of methanol and CO, because it's easier to work with moles than the grams

moles of methanol = 15/32 = 0.469 moles

moles of CO = 10/28 = 0.357 moles

According to the equation 1 mole of methanol reacts completely with 1 mole of CO. However, in this case, we can see that methanol exceed the CO, so, the CO is the limitant reactant so:

moles reactants of methanol: 0.469 - 0.357 = 0.112 moles.

moles of acid produced: 0.357 moles

This is because we have a ratio of 1:1 between methanol and CO. As methanol exceed CO, the CO is consumed completely leaving a remanant of methanol behind. the whole moles of CO are used, and appears as product of acetic acid, therefore, the moles of acetic acid are the same of CO.

Now with the molar mass of acid, let's calculate the gram of acid, and yield:

g = 0.357 * 60 = 21.42 g of acetic acid.

This is the theorical yield of acetic acid.

5 0
4 years ago
HEEEEeEELP PLEasE! IS SCIENCE
Fynjy0 [20]
Gas and radio waves I’m pretty sure is correct
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3 years ago
cyclopropane is a commonly used anesthetic. If a 2.00 L flask contains 3.11 g of cyclopropane gas at 684 mmHg pressure and 23.0
jeka94

Answer:

42.0g/mol

Explanation:

The steps for this question is to use the ideal gas law, and then use n=m/M to find molar mass.

PV = nRT

n= PV/RT

Change 23 degrees to 296.15 K and 684mmHg to kpa

n = (91.1925kpa)(2.00L)/(8.314Lkpa/mol K)(296.15K)

n= 0.074mol

n = m/M

M = m/n

M = 41.98489g/mol

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2 years ago
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