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Svet_ta [14]
3 years ago
5

Which solution has the highest boiling point at standard pressure?

Chemistry
1 answer:
artcher [175]3 years ago
6 0
<span>The correct answer is 3: 0.10 M K3PO4(aq). The higher the concentration (or molarity), the higher the boiling point. Thus, the solution with the most moles will have the highest boiling point. SO4, PO4, and NO3 are all polyatomic ions, so by definition, they only have one mole. In K3PO4, K3 has 3 moles and PO4 has 1 mole, meaning all together it has 4 moles (more than any of the other options).</span>
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Which statements about the equation shown above are correct? Check all that apply. It represents a reaction that involves rearra
mezya [45]

Answer: a and c

Explanation:

6 0
3 years ago
Read 2 more answers
A gas sample is found to contain 39.10% carbon, 7.67% hydrogen, 26.11% oxygen, 16.82% phosphorus, and 10.30% fluorine. If the mo
Doss [256]

Answer:

C6H14O3F

Explanation:

The first step is to divide each compound by its molecular weight

Carbon

= 39.10/12

= 3.258

Hydrogen

= 7.67/1

= 7.67

Oxygen

= 26.11/16

= 1.63

Phosphorous

= 16.82/31

= 0.542

Flourine

= 10.30/19

= 0.542

The next step is to divide by the lowes value

3.258/0.542

= 6 mol of C

7.67/0.542

= 14 mol of H

1.63/0.542

= 3 mol of O

0.542/0.542

= 1 mol of P

0.542/0.542

= 1 mol of F

Hence the molecular formula is C6H14O3F

5 0
3 years ago
Why was Newland’s periodic table rejected?
Rina8888 [55]
He put iron with sulfur and oxygen and it had a few more errors and iron is a metal the other two are nonmetals

5 0
3 years ago
A 1.0-L buffer solution is 0.10 M in HF and 0.050 M in NaF. Which action destroys the buffer? (a) adding 0.050 mol of HCl (b) ad
Volgvan

Answer:

(a) adding 0.050 mol of HCl

Explanation:

A buffer is defined as the mixture of a weak acid and its conjugate base -or vice versa-.

In the buffer:

1.0L × (0.10 mol / L) = 0.10 moles of HF -<em>Weak acid-</em>

1.0L × (0.050 mol / L) = 0.050 moles of NaF -<em>Conjugate base-</em>

-The weak acid reacts with bases as NaOH and the conjugate base reacts with acids as HCl-

Thus:

<em>(a) adding 0.050 mol of HCl:</em> The addition of 0.050moles of HCl produce the reaction of 0.050 moles of NaF producing HF. That means after the reaction, all NaF is consumed and you will have in solution just the weak acid <em>destroying the buffer</em>.

(b) adding 0.050 mol of NaOH: The NaOH reacts with HF producing more NaF. Would be consumed just 0.050 moles of HF -remaining 0.050 moles of HF-. Thus, the buffer <em>wouldn't be destroyed</em>.

(c) adding 0.050 mol of NaF: The addition of conjugate base <em>doesn't destroy the buffer</em>

3 0
3 years ago
Although Rutherford is credited with the famous gold foil scattering experiment, he didn’t actually conduct this experiment hims
Dmitrij [34]
Although he did not do the experiment himself, he had come up with the idea of what to do and how to do it. I think that only Rutherford receiving credit is okay as the assistants did not do anything to contribute to the actual idea of the experiment.
For example, we credit the invention of the iPhone to Steve Jobs, the engineers of Apple, the designers, etc. - those with actual contributions to the invention and the ideas and not the Chinese factory workers - those who construct the iPhone itself. 
3 0
4 years ago
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