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ziro4ka [17]
3 years ago
5

Select the correct answer.

Chemistry
2 answers:
alexandr402 [8]3 years ago
8 0
Option D
Step by step explanation:
jasenka [17]3 years ago
7 0

Answer:

D

Explanation:

plato

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How many electrons in an atom can have each of the following quantum number or sublevel designations?
Karo-lina-s [1.5K]

Answer: (a) 2 (b) 6 (c) 14

Explanation:

In the Azimuthal quantum number(l) electrons in a particular subshell (such as s, p, d, or f) are defined by values of l (0, 1, 2, or 3).

s is l=0, p is l=1, d is l=2, f is l=3.

The magnetic quantum number (ml)  The value of ml can range from -l to +l, including zero. Thus the s, p, d, and f subshells contain 1, 3, 5, and 7 orbitals each, with values of m within the ranges 0, ±1, ±2, ±3 respectively. Each shell can have 2 x l + 1 sublevels, and each of these sublevel can accommodate up to two electrons.

(a) n=2, l=1, ml=0. If l=1 then 2 x 1+ 1=3 sublevels, 3*2=6 electrons. When l=1, ml =-1,0,+1, ml=0  accommodate two(2)electrons

(b) 5p. p is l=1  If l=1 then 2 x 1+ 1=3 sublevels, 3*2= electrons. This means in the 5 shell, the p orbital has 3 subshell and accommodate 6 electrons.

(c) n = 4, l = 3 if l=3 then 2 x 3+ 1=7 sublevel 7*2=14 electrons. This means the in the 4 shell, the f orbital has 7 subshell and accomdate 14 elections.

7 0
2 years ago
C. What is oxidized in the reaction? What is reduced? (2 points)
Rina8888 [55]

Answer:

Oxidation: a type of chemical reaction where one or more electrons are lost.

Oxidation State / Number: a number assigned to an atom describing its degree of oxidation, meaning how many electrons it has gained or lost.

Reduction: a type of chemical reaction where one or more electrons are gained.

Oxidation-Reduction Reaction: a chemical reaction where oxidation and reduction occurs simultaneously

Explanation:

Reduction always occurs at cathode

Oxidation always occurs in anode

These two process occurs in same way independent of nature of cell whether voltaic or electrolytic.

6 0
2 years ago
What is the half-life (in seconds) of a zero-order reaction which has an initial reactant concentration of 0.884 M with a k valu
pantera1 [17]
<span>Answer: 8.15s
</span><span />

<span>Explanation:
</span><span />

<span>1) A first order reaction is that whose rate is proportional to the concenration of the reactant:
</span><span />

<span>r = k [N]
</span><span />

<span>r = - d[N]/dt =
</span><span />

<span>=> -d[N]/dt = k [N]
</span><span />

<span>2) When you integrate you get:
</span><span />

<span>N - No = - kt
</span>
<span></span><span /><span>
3) Half life => N = No / 2, t = t'
</span><span />

<span>=> No - No/ 2 = kt' => No /2 = kt' => t' = (No/2) / k
</span><span />

<span>3) Plug in the data given: No = 0.884M, and k = 5.42x10⁻²M/s
</span>
<span /><span /><span>
t' = (0.884M/2) / (5.42x10⁻²M/s) = 8.15s</span>
6 0
2 years ago
Read 2 more answers
Sterling silver is 92.5% silver and 7.5% copper. Its density is 10.25 g/cm3. A sterling silver pendant is added to a graduated c
Mariulka [41]

From the information given:

  • The volume of the graduated cylinder = 50.0 mL
  • when a sterling silver pendant is added, the volume increases to = 61.3 mL

∴

The volume of the sterling silver pendant is:

= 61.3 mL - 50.0 mL

= 11.3 mL

Since, 1 mL = 1cm³

Then;

11.3 mL = 11.3 cm³

  • the density of the sterling silver = 10.25 g/cm³

Using the relation for Density; i.e.

\mathbf{Density = \dfrac{mass}{volume}}

\mathbf{10.25 \ g/cm^3= \dfrac{mass}{11.3  \ cm^3}}

mass = 10.25 g/cm³× 11.3 cm³

mass of the sterling silver = 115.825 grams

Recall that sterling silver has:

  • 92.5% silver and;
  • 7.5% copper

∴

The mass of the copper contained in the sterling silver pendant can be calculated as:

\mathbf{= \dfrac{115.825  \ g \times 7.5}{100}}

= 8.687 grams

Therefore, we can conclude that the mass of the copper contained in the sterling silver pendant is 8.687 grams

Learn more about the relation between Density, Mass, and Volume here:

brainly.com/question/24386693?referrer=searchResults

4 0
2 years ago
Determine the molar mass of CaO
Umnica [9.8K]
56.0774 g/mol just took the test
5 0
3 years ago
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