Dang bro that stuff is really hard I’m defiantly on a lower grade lol
The answer is B particles combine into a large amount of engery.
Answer: 5.47m/s
Explanation:
Mass = 72.3kg
K.E = 1080.0J
V =?
K.E = 1 /2MV^2
V^2 = 2K.E /M = (2x1080)/72.3
V = sqrt [(2x1080)/72.3]
V = 5.47m/s
Ammonia undergoes combustion with oxygen to produce nitric oxide and water. The volume of the oxygen required to react with 720 ml of ammonia is 900 ml.
<h3>What is volume?</h3>
Volume is the area occupied by the substance and is the ratio of the mass to the density.
At STP, 1 mole of gas occupies 22.4 L of volume
Given,
Volume of ammonia reacted = 0.720 L
The combustion reaction is shown as,

From the stoichiometry of the reaction, it can be said that,
L of ammonia reacts with
L of oxygen gas.
So, 0.720 L of ammonia will react with:

Therefore, the volume of oxygen required is 900 mL.
Learn more about volume here:
brainly.com/question/14090111
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