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Aleks [24]
3 years ago
8

What type of graphic image is shown in Image 12

Chemistry
1 answer:
Elanso [62]3 years ago
4 0

Answer:

C. Timeline

Explanation:

Sorry if I was wrong

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Match the letters with the correct part of the flower
shepuryov [24]
Here is a photo to help you out.  

3 0
3 years ago
A gas has a pressure of 851mmHg at 330.K. What will its temperature be at 990.mmHg?
aev [14]

Answer:

383.90K

Explanation:

P1 = 851mmHg

T1 = 330K

T2 = ?

P2 = 990mmHg

To solve for P2, we have to use pressure law which states that the pressure of a fixed mass of fixed is directly proportional to its temperature provided that volume remains constant

Mathematically,

P = kT, k = P/T

P1 / T1 = P2 / T2 = P3 / T3 =.......=Pn / Tn

P1 / T1 = P2 / T2

T2 = (P2 × T1) / P1

T2 = (990 × 330) / 851

T2 = 383.90K

The final temperature of the gas is 383.90K

3 0
4 years ago
Calculate the fraction of atoms in a sample of argon gas at 400 K that have an energy of 12.5 kJ or greater. Report your answer
emmainna [20.7K]

Answer:

0.023

Explanation:

The Arrhenius' equation states that:

k = A*e^{\frac{-Ea}{RT}

Where k is the velocity constant of the reaction, A is the constant of the collisions, Ea is the activation energy (the energy necessary to the molecules have so the reaction will happen), R is the gas constant (8.314 J/molK) and T is the temperature.

This equation is derivated of:

k = pZf

Where

p=fraction of collisions that occur with reactant molecules properly oriented

f=fraction of collisions having energy greater than the activation energy

Z=frequency of collisions

Thus, p*Z = A, and

f = e^{\frac{-Ea}{RT} }

So, if the energy of the molecules is 12.5 kJ/mol = 12500 J/mol, thus the fraction will be:

f = e^{\frac{-12500}{8.314*400} }

f = 0.023

6 0
3 years ago
Which of the following graphs correctly represents the relationship between the temperature and the volume of an ideal gas that
Anon25 [30]

Answer:

The graph of the relationship of temperature one volume is a graphical representation of Charles law.

Explanation:

The graph shows the relationship between volume vs temperature plotted at constant pressure for a fixed amount of gas. As can be observed from the graph, the volume increases with an increase in the temperature, and vice versa. Thus, volume is directly proportional to temperature at a constant pressure, which is the statement of Charles's law.

Volume is plotted on the y- axis, and temperature is on x-axis. The graph is a straight line with a positive slope passing the origin. The equation of the line is V = kT, which is the equation of Charles's law. The slope of the line is k. As temperature approaches zero kelvin, volume also approaches zero.

Real gases do not obey Charles's law at low temperatures. As temperature approaches absolute zero (0 K), the real gases start deviating significantly from Charles's law.

4 0
3 years ago
Plz help due tomorrow what are the answers 1-5 will be marked brainliest
lina2011 [118]

1.)D

2.)B

3.)A

4.)C

5.)C

6 0
3 years ago
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