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3 years ago

How can scientists determine when a radioactive substance will no longer be dangerous

Chemistry

1 answer:

LekaFEV [45]3 years ago

7 0

They can probably use those radioactive measuring things. But they will still use proper caution around it.

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I2(g) + Cl2(g)2ICl(g) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 1.62 mol

galina1969 [7]

Answer:

The change in entropy of the surrounding is -146.11 J/K.

Explanation:

Enthalpy of formation of iodine gas = $\Delta H_f_{(I_2)}=62.438 kJ/mol$

Enthalpy of formation of chlorine gas = $\Delta H_f_{(Cl_2)}=0 kJ/mol$

Enthalpy of formation of ICl gas = $\Delta H_f_{(ICl)}=17.78 kJ/mol$

The equation used to calculate enthalpy change is of a reaction is:

$\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]$

For the given chemical reaction:

$I_2(g)+Cl_2(g)\rightarrow 2ICl(g),\Delta H_{rxn}=?$

The equation for the enthalpy change of the above reaction is:

$\Delta H_{rxn}=[(2\times \Delta H_f_{(ICl)})]-[(1\times \Delta H_f_{(I_2)})+(1\times \Delta H_f_{(Cl_2)})]$

$=[2\times 17.78 kJ/mol]-[1\times 0 kJ/mol+1\times 62.436 kJ/mol]=-26.878 kJ/mol$

Enthaply change when 1.62 moles of iodine gas recast:

$\Delta H= \Delta H_{rxn}\times 1.62 mol=(-26.878 kJ/mol)\times 1.62 mol=-43.542 kJ$

Entropy of the surrounding = $\Delta S^o_{surr}=\frac{\Delta H}{T}$

$=\frac{-43.542 kJ}{298 K}=\frac{-43,542 J}{298 K}=-146.11 J/K$

1 kJ = 1000 J

The change in entropy of the surrounding is -146.11 J/K.

4 0

3 years ago

Which of the following most likely happens when the volume of a gas increases the number of collisions of gas particles remains

lord [1]

When the collision of gas particles and the volume of the gas stay the same it causes a chemical.

5 0

4 years ago

Read 2 more answers

If the federal government wants to encourage businesses and consumers to spend more money, it would MOST LIKELY

ICE Princess25 [194]

If the federal government wants to encourage businesses and consumers to spend more money, it would most likely to reduce the price of the goods to attract more buyers and sellers

6 0

4 years ago

Read 2 more answers

Suppose you massed out 18.95 g of sodium carbonate (Na2CO3). How many moles<br> would you have?

Westkost [7]

Answer:

3.50

Explanation:

6 0

3 years ago

Complete combustion of 2.0 metric tons of coal to gaseous carbon dioxide releases 6.6X10¹⁰ J of heat. Convert this energy to

Taya2010 [7]

First of all we should know that, 1 Joule = 0.000239 kilocalories.

So, 6.6× $10^{10}$ J = 6.6× $10^{10}$ × 0.000239 kilocalories

6.6× $10^{10}$ J = 15774000 kilocalories

= 1.58 × $10^{7}$ kilocalories

One joule is described as the quantity of electricity exerted when a pressure of 1 newton is implemented over a displacement of 1 meter. Within the SI machine, the unit of labor or electricity is the Joule.

The kilocalorie, or meals calorie, is the quantity of warmth required to elevate one kilogram of water 1 °C. warmness capability is the amount of heat required to raise one gram of material 1 °C beneath steady pressure. A kilocalorie is the amount of warmth required to raise the temperature of 1 kilogram of water one diploma Celsius.

Learn more about joule here:-

brainly.com/question/490326

#SPJ4

6 0

2 years ago