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nalin [4]
2 years ago
11

What is the best definition of solar radiation?Storing Storing of of energy energy in in Earth'Earth's s oceansoceansEnergy Ener

gy from from the the Sun Sun that that reaches reaches EarthEarthMoisture Moisture and and heat heat energy energy in in the the atmosphereatmosphereIncreased Increased evaporation evaporation due due to to warm warm waterwater
Chemistry
1 answer:
mariarad [96]2 years ago
6 0

Answer:The solar energy that we receive through solar radiation is directly or indirectly responsible for aspects as important to life as: Photosynthesis in plants; maintaining a planet temperature compatible with life. of the wind. The solar energy that reaches the earth's surface is 10,000 times greater than the energy currently consumed by all

Explanation:

You might be interested in
Need help ASAP!!!! what is the value (angle) for the C=C=O bond in Ketene i.e. CH2=C=O
stepan [7]

Answer:

180^\circ by the VSEPR theory.

Explanation:

This question is asking for the bond angle of the \rm C=C=O bond in \rm H_2C=C=O. The VSEPR (valence shell electron pair repulsion) theory could help. Start by considering: how many electron domains are there on the carbon atom between these two bond?

Note that "electron domains" refer to covalent bonds and lone pairs collectively.

  • Each nonbonding pair (lone pair) of valence electrons counts as one electron domain.
  • Each covalent bond (single bond, double bond, or triple bond) counts as exactly one electron domain.

For example, in \rm H_2C=C=O, the carbon atom at the center of that \rm C=C=O bond has two electron domains:

  • This carbon atom has two double bonds: one \rm C=C bond and one \rm C=O bond. Even though these are both double bonds, in VSEPR theory, each of them count only as one electron domain.
  • Keep in mind that there are only four valence electrons in each carbon atom. It can be shown that all four valence electrons of this carbon atom are involved in bonding (two in each of the two double bonds.) Hence, there would be no nonbonding pair around this atom.

In VSEPR theory, electron domains around an atom repel each other. As a result, they would spread out (in three dimensions) as far away from each other as possible. When there are only two electron domains around an atom, the two electron domains would form a straight line- with one domain on each side of the central atom. (To visualize, consider the three atoms in this \rm C=C=O bond as three spheres on a stick. The central \rm C atom would be between the other \rm C atom and the \rm O atom.)

This linear geometry corresponds to a bond angle of 180^\circ.

3 0
3 years ago
If 4.0 mol aluminum and 7.0 mol hydrogen bromide react according to the following equation, how many moles of hydrogen are forme
Vinil7 [7]

Answer:

Moles of hydrogen formed = 3.5 moles

Explanation:

Given that:-

Moles of aluminium= 4.0 mol

Moles of hydrogen bromide = 7.0 mol

According to the reaction:-

2Al_{(s)}+6HBr_{(aq)}\rightarrow 2AlBr_3_{(aq)}+3H_2_{(g)}

2 moles of aluminum react with 6 moles of hydrogen bromide

1 mole of aluminum react with 6/2 moles of hydrogen bromide

4 moles of aluminum react with (6/2)*4 moles of hydrogen bromide

Moles of hydrogen bromide = 12 moles

Available moles of hydrogen bromide = 7.0 moles

Limiting reagent is the one which is present in small amount. Thus, hydrogen bromide is limiting reagent. (7.0 < 12)

The formation of the product is governed by the limiting reagent. So,

6 moles of hydrogen bromide on reaction forms 3 moles of hydrogen

1 moles of hydrogen bromide on reaction forms 3/6 moles of hydrogen

7 moles of hydrogen bromide on reaction forms (3/6)*7 moles of hydrogen

<u>Moles of hydrogen formed = 3.5 moles</u>

3 0
3 years ago
NEED HELP FAST!20 pts for an easy worksheet
rjkz [21]
On the bottom
1. sharing electrons
2. the middle two dots between the F:F
5 0
3 years ago
An engine needs a replacement part that will be exposed to high heat. A(n) _____ would be the best type of material to use to ma
Jobisdone [24]
I think it might be lead? I'm not quite too sure though. You might have to research more into it.
7 0
2 years ago
Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
viva [34]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

6 0
3 years ago
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