<h2>Solving Quadratic Equations with the Quadratic Formula</h2>
<h3>Answer:</h3>
and 
<h3>Step-by-step Explanation: </h3>
Recall:
if we have a quadratic equation, 
, where 
, 
and 
are real numbers and 
, 
.
Given:
Solving for 
:
Solving with the positive value:
Solving with the negative value:
we are given
f(x)=[x=1]
where bracket means ceiling functions
we know that
Ceiling function returns the least value of the integer that is greater than or equal to the specified number
so, we can check each options
option-A:
At x=-4:
f(x)=[-4-1] =-5
For x<-3:
Let's assume
x=-3.1
f(x)=[-3.1-1] =[-4.1]=-5
so, this interval is TRUE
option-B:
At x=-2:
f(x)=[-2-1] =-3
For x<-1:
Let's assume
x=-1.1
f(x)=[-1.1-1] =[-2.1]=-3
so, this is FALSE
Answer:
16 1/4 or 65/4
Step-by-step explanation:
If you are describing transformations with respect to the graph of f(x) = x:
f(x) = x has no transformation
g(x) = (x+2) - 3 is the graph of f(x) translated 2 units left and 3 units down
2(h(x) = x-1) is the graph of f(x) vertically expanded by a factor of 2 and then translated 1 unit right
d(x) = 1/2x + 2 is the graph of f(x) vertically compressed by a factor of 1/2 and then translated 2 units up
Answer:
=2x+46
Step-by-step explanation:
If your wanting me to check your work then yes you got it right the anwser is =2x+46.
