A=+ or - 5 bc -5x-5 or 5x5 equals to 25
#5 is 4, #6 is graph A, and #7 is graph B. I hope this helped, Please mark as brainliest because I am 3 more away from the next level.
Answer:
a) W₁ = 78400 [J]
b)Wt = 82320 [J]
Step-by-step explanation:
a) W = ∫ f*dl general expression for work
If we have a chain with density of 10 Kg/m, distributed weight would be
9.8 m/s² * 10 kg = mg
Total length of th chain is 40 m, and the function of y at any time is
f(y) = (40 - y ) mg where ( 40 - y ) is te length of chain to be winded
At the beggining we have to wind 40 meters y = 0 at the end of the proccess y = 40 and there is nothing to wind then:
f(y) = mg* (40 - y )
W₁ = ∫f(y) * dy ⇒ W₁ = ∫₀⁴⁰ mg* (40 - y ) dy ⇒ W₁ = mg [ ∫₀⁴⁰ 40dy - ∫₀⁴⁰ ydy
W₁ = mg [ 40*y |₀⁴⁰ - 1/2 * y² |₀⁴⁰ ⇒ W₁ = mg* [ 40*40 - 1/2 (40)² ]
W₁ = mg * [1/2] W₁ = 10*9,8* ( 800 )
W₁ = 78400 [J]
b) Now we can calculate work to do if we have a 25 block and the chain is weightless
W₂ = ∫ mg* dy ⇒ W₂ = ∫₀⁴⁰ mg*dy ⇒ W₂ = mg y |₀⁴⁰
W₂ = mg* 40 = 10*9.8* 40
W₂ = 3920 [J]
Total work
Wt = W₁ + W₂ ⇒ Wt = 78400 + 3920
Wt = 82320 [J]
Answer:
6748'
Step-by-step explanation:
The long diagonal is the third leg of a triangle with the given side lengths and an angle between them that is the supplement of the given angle. Its length can be found from the Law of Cosines.
a^2 = b^2 +c^2 -2bc·cos(A)
a^2 = 3473^2 +4822^2 -2·3473·4822·cos(180° -72.23°)
a^2 = 45,535,553.83
a ≈ 6748.004
The longer diagonal is about 6758 feet long.
Answer:
5 years ago
Let Kelly's age be x
Jake's age is 4x
5 years later
Kelly's age is x + 5
Jake's age is 4x+5
The sum of both their ages is 60. The equation will be
x + 5 + 4x + 5 = 60
5x + 10 = 60
5x = 60 - 10
x = 50/5 = 10
So Kelly is (10 + 5) 15 years old.
Jake is (4*10 + 5) = 45 years old
