This is a quadratic formula with a general form of a²x + bx + c = 0. For quadratic equations, we can solve for its two roots using the quadratic formula shown in the attached picture.
a = -3
b = -4
c = -4
x = [-(-4) + √(-4)² - 4(-3)(-4)]/2(-3) =
<em>2 + √-32/2</em>x = [-(-4) - √(-4)² - 4(-3)(-4)]/2(-3) =
<em> 2 - √-32/2</em>
So 4 inches diameter result the radius is 4/2 = 2 inches
area of base = pir^2 = 3,14*2^2 = 3,14*4 = 12,56 inches squared
volume = area of base *height
V = 12,56 *9 = 113,04 so rounded 113,05 inches cubed
hope this will help you
Answer:
deigo
Step-by-step explanation:
both has de same velocity but diego ran more than the other
Answer:
The sample size is 
Step-by-step explanation:
From the question we are told that
The sample proportion is 
The margin of error is 
Given that the confidence level is 95% the level of significance is mathematically represented as



Next we obtain the critical value of
from the normal distribution table , the values is

The reason we are obtaining critical value of
instead of
is because
represents the area under the normal curve where the confidence level interval (
) did not cover which include both the left and right tail while
is just the area of one tail which what we required to calculate the margin of error
Generally the margin of error is mathematically represented as

substituting values




=> 
The answer to this question will be A