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avanturin [10]
3 years ago
11

Express 5.412 hours to the nearest minute

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:323.72

Step-by-step explanation:

Begin by multiplying 60 by 5 hours.

Then 60 minutes by 0.412

uysha [10]3 years ago
5 0

Step-by-step explanation:

1h = 60min \\ 5.412h = x \\  \\ cross \:  \:  \: multiple \\ 1x = 60 \times 5.412 \\ 1x = 324.72 \\  \frac{1x}{1}  =  \frac{324.72}{1}  \\ x = 324.72min

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A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.
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1. Divide wire b in parts x and b-x. 

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= \frac{1}{2}sin60^{o}side*side=   \frac{1}{2} \frac{ \sqrt{3} }{2}  (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}
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3. Let x be the circumference of the circle.

 2 \pi r=x

so r= \frac{x}{2 \pi }

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4. Let f(x)=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)=\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0

(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b

x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

6. So one part is \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) } and the other part is b-\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }

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$17 (it's just the market price - the marginal cost)
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