Answer:
The answer to your question is 8 h
Step-by-step explanation:
Data
length of the ladder = 200 cm
distance between each rung = 20 cm
rate = 10 cm/h
fifth rung = ?
Process
1.- Calculate the total distance the tide must rise
distance = 20 cm x 4
= 80 cm because the first rung touches the water
2.- Calculate the time
rate = distance / time
-Solve for time
time = distance / rate
-Substitution
time = 80 cm / 10cm/h
-result
time = 8 h
Answer:
First diagonal: 7.874
Second diagonal: 8.3666
Step-by-step explanation:
We use the Pythagorean Theorem to find these.
First diagonal = 5²+6²=c²
25+36=c²
61=c²
√61=c
c=7.874
Then we use that to find the second diagonal.
7.874²+3²=c²
61+9=c²
70=c²
√70=c
c=8.3666
The system is almost right! The issue here is: when Sharon was adding the systems, she made a mistake. 15 + 9 = 24 not 26. From there, the rest of her steps are correct. Hope this helps!
9514 1404 393
Answer:
-16
Step-by-step explanation:
The absolute value function gives the positive value of the argument, so this is ...
-4|-4| = -4·4 = -16
Answer:
Step-by-step explanation:
By definition, 
and 
. Since since 
is negative, 
must also be negative, and since 
is positive, we must be in Quadrant II.
In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.
To find the remaining leg, use to the Pythagorean Theorem, where 
, where 
is the hypotenuse, or longest side, of the right triangle and 
and 
are the two legs of the right triangle.
Solving, we get:
Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.
Thus, we have:
