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rjkz [21]
3 years ago
14

Line ef is tangent to circle G at point P. The the measure of cae is 95, what is the measure of cba

Mathematics
2 answers:
Elenna [48]3 years ago
6 0

Answer: the answers 190

Step-by-step explanation:

rosijanka [135]3 years ago
3 0

Answer:

The answer is C. 190

Step-by-step explanation:

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The volume of a rectangular prism is 2,100 cm cubed , with length 25 cm and width 12 cm. What is the height, in cm?
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Mark wants to improve his free throw percentage in basketball He has shot 1,250 free throws over the last 20 days. He shot eithe
Sedaia [141]
Let's use a for number of days when he shot 50 shots and b for number of days when he shot 100 shots.
We have:
a + b = 20

We also know that he shot total of 1250 shots:
50a + 100 b = 1250

We have two equations. We can solve them for a and b.  Let's rearange first equation for a:
a= 20 - b
We insert this into second equation:
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Mark shot 100 shots on 5 days.
4 0
3 years ago
a bag contains only red and blue counters. there are 6 more red than blue a counter is chosen at random. the probability is 1/4.
xxMikexx [17]

Answer:

Avoid guessing or choosing an answer you are unsure of. Remember, you’ll only get the extra points if you give the correct answer.

Step-by-step explanation:

4 0
3 years ago
A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by ℎ = −16푡 ଶ+103푡+5 w
Liono4ka [1.6K]

Question:

A fastball is hit straight up over home plate. The ball's height, h (in feet), from the ground is modeled by h(t)=-16t^2+80t+5, where t is measured in seconds.  Write an equation to determine how long it will take for the ball to reach the ground.

Answer:

t = 5.0625

Step-by-step explanation:

Given

h(t)=-16t^2+80t+5

Required

Find t when the ball hits the ground

This implies that h(t) = 0

So, we have:

0=-16t^2+80t+5

Reorder

-16t^2+80t+5 = 0

Using quadratic formula, we have:

t = \frac{-b\±\sqrt{b^2 - 4ac}}{2a}

Where

a = -16      b =80      c = 5

So, we have:

t = \frac{-80\±\sqrt{80^2 - 4*-16*5}}{2*-16}

t = \frac{-80\±\sqrt{6400 +320}}{-32}

t = \frac{-80\±\sqrt{6720}}{-32}

t = \frac{-80\±82.0}{-32}

This gives:

t = \frac{-80+82.0}{-32} or t = \frac{-80-82.0}{-32}

t = \frac{2}{-32} or t = \frac{-162}{-32}

t = -\frac{2}{32} or t = \frac{162}{32}

But time can not be negative.

So, we have:

t = \frac{162}{32}

t = 5.0625

<em>Hence, time to hit the ground is 5.0625 seconds</em>

3 0
3 years ago
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