Question

Calculate the total resistance in a series circuit made up of resistances of 3Ω, 4Ω, and 5Ω.

Answer 1

The equivalent resistance of three resistors in series is given by the sum of the resistances:
$R_{eq}=R_1+R_2+R_3$
In this circuit, the value of the three resistances is:
$R_1=3 \Omega$
$R_2=4 \Omega$
$R_3=5 \Omega$
Therefore, the equivalent resistance of the circuit is:
$R_{eq}=3 \Omega+4 \Omega + 5 \Omega =12 \Omega$