Using Kepler's 3rd law which is: T² = 4π²r³ / GM
Solved for r :
r = [GMT² / 4π²]⅓
Where G is the universal gravitational constant,M is the mass of the sun,T is the asteroid's period in seconds, andr is the radius of the orbit.
Change 5.00 years to seconds :
5.00years = 5.00years(365days/year)(24.0hours/day)(6... = 1.58 x 10^8s
The radius of the orbit then is computed:
r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.58 x 10^8s)² / 4π²]⅓ = 4.38 x 10^11m
Answer
given,
k = 250 N/m
q = 900 N/m³
(FSp)s=−kΔs−q(Δs)^3
work done = Force x displacement

limits are x = 0 to x = 0.15 m
work done

![W = [\dfrac{kx^2}{2}+\dfrac{qx^4}{4}+ C]_0^0.15](https://tex.z-dn.net/?f=W%20%3D%20%5B%5Cdfrac%7Bkx%5E2%7D%7B2%7D%2B%5Cdfrac%7Bqx%5E4%7D%7B4%7D%2B%20C%5D_0%5E0.15)

W = 3.375 + 0.1139
W = 3.3488 J
b) % cubic term =
% cubic term =
Answer:
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Explanation:
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Answer:
.
Explanation:
If the mass of an object is
and the velocity of that object is
, the linear momentum of that object would be
.
Assume that the initial velocity of the mass is positive (
.) However, the direction of the velocity is reversed after the impact. Thus, the sign of the new velocity of the object would be negative- the opposite of that of the initial velocity. The new velocity would be
.
Thus, the change in the velocity of the mass would be:
.
The change in the linear momentum of the mass would be:
.
Thus, the magnitude of the change of the linear momentum would be
.
A mechanical wave moves through all matter