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rosijanka [135]

3 years ago

9

If Matthew was traveling into space from Earth, which of these would he be able to reach first? A) Sun B) Venus C) Alpha centaur

i D) not enough information given

1 answer:

const2013 [10]3 years ago

3 0

C.) Alpha Centauri

Explanation:

Due to it being the closest planetary system to earth.

About 4.367 light years away.

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The scalar product of two vectors 2N,4N is 4 angle between them

Angelina_Jolie [31]

Answer:

60°

Explanation:

The scalar product of two vectors with an angle ∅ between them is defined as:

$\overrightarrow{a}\cdot \overrightarrow{b}=|a||b|cos\phi$

Solving for angle ∅:

$\phi= cos^{-1}(\frac{\overrightarrow{a}\cdot \overrightarrow{b}}{|a||b|})=cos^{-1}(\frac{4}{8})$

7 0

3 years ago

Which of the things below have matter? There is more than 1 answer.

JulijaS [17]

Answer:

car and a can

Explanation:

3 0

3 years ago

A helicopter is rising straight up. the height of a helicopter above the ground is given by h = 3.50t3, where h is in meters and

allochka39001 [22]

First, we need to calculate for the height where the mailbag was dropped.

h = 3.50 * t^3

at t = 1.75 s, h is:

h = 3.50 * (1.75)^3

h = 18.758 m

Then we can use the equation to solve for time:

h = v0t + 0.5gt^2

where v0 is initial velocity = 0, t = time, g = acceleration due to gravity

18.758 m = 0 + 0.5 * (9.81 m/s^2) * t^2

t^2 = 3.8242

t = 1.96 s

<span>So the mailbag reaches the ground after 1.96 seconds</span>

5 0

3 years ago

15.6 grams of lead(II) nitrate is in a test tube. A 4.8-g sample of potassium iodide is an Erlenmeyer flask. The substance in th

miv72 [106K]

<u>Answer:</u>

Mass of combined products = 20.4 grams

Mass of combined product and Erlenmeyer flask = 136 grams

<u>Explanation:</u>

By law of mass conservation, mass cannot be destroyed or created. So mass before reaction is mass after reaction.

Mass of lead(II) nitrate = 15.6 grams

Mass of potassium iodide = 4.8 grams

Mass of the Erlenmeyer flask = 115.6 grams

Mass of reactants = 15.6 + 4.8 = 20.4 grams

So mass of products = 20.4 grams

Mass of combined product and Erlenmeyer flask = 115.6 + 20.4 = 136 grams

6 0

3 years ago

1. Bone has a Young’s modulus of about

Blababa [14]

#1

As we know that

$Y = \frac{stress}{strain}$

now plug in all data into this

$1.8\times 10^{10} = \frac{1.68 \times 10^8}{strain}$

$strain = 9.33 \times 10^{-3}$

now from the formula of strain

$strain = \frac{\Delta L}{L}$

$9.33 \times 10^{-3} = \frac{\Delta L}{0.54}$

$\Delta L = 5.04 \times 10^{-3} m$

$\Delta L = 5.04 mm$

#2

As we know that

pressure * area = Force

here we know that

$Area = 3.53 \times 11.6 = 40.95 m^2$

$P = 0.2 atm = 0.2 \times 1.01 \times 10^5 = 2.02\times 10^4 Pa$

now force is given as

$F = 40.95 \times (2.02\times 10^4) = 8.27 \times 10^5 N$

#3

As we know that density of water will vary with the height as given below

$\rho = \frac{\rho_0}{1 - \frac{\Delta P}{B}}$

here we know that

$\Delta P = 2600 atm = 2600 \times 1.01 \times 10^5 = 2.63\times 10^8 Pa$

$B = 2.3 \times 10^9 N/m^2$

now density is given as

$\rho = \frac{1050}{1 - \frac{2.63\times 10^8}{2.3 \times 10^9}}$

$\rho = 1185.3 kg/m^3$

#4

as we know that pressure changes with depth as per following equation

$P = P_o + \rho g h$

here we know that

$P = 3 P_0$

now we will have

$3P_0 = P_0 + \rho g h$

$2P_0 = \rho g h$

$2(1.01 \times 10^5) = 1025 (9.81)(h)$

here we will have

$h = 20.1 m$

so it is 20.1 m below the surface

#5

Here net buoyancy force due to water and oil will balance the weight of the block

so here we will have

$mg = \rho_1V_1g + \rho_2V_2g$

$A(0.0476)979 = 922(A)(0.0476 - x) + 1000(A)(x)$

$46.6 = 43.89 - 922x + 1000x$

$x = 3.48 cm$

so it is 3.48 cm below the interface

5 0

4 years ago