All categories

3 years ago

Select the volume units that are greater than one liter.

Physics

2 answers:

AysviL [449]3 years ago

8 0

Answer: The correct answers are option (a)and(c).

Explanation:

1) In ,1 kilo Liter = 1,000 Liter

1 liter = 0.001 kilo Liter

2) In ,1 Mega Liter = 1,000,000

1 Liter = $10^{-6}$ Mega Liter

Where as milliliter, centiliter, deciliter and nano liters are smaller units that 1 liter

1 Liter = 1000 milliliter

1 Liter = 100 centiliter

1 Liter = 10 deciliter

1 Liter = $10^9$ nano liter

Hence, the correct answers are option (a)and(c).

Andreas93 [3]3 years ago

5 0

A.) kiloliter. 1 kiloliter = 1,000 liters
c.) megaliter. 1 megaliter = 1,000,000 liters

hope this helps

You might be interested in

What physical property makes the red light different from blue light, or radio waves different from microwaves?

inna [77]

Only their wavelength does.

Blue light waves have only roughly half the wavelength of red light waves, and the so-called "microwaves" are the radio waves with the shortest wavelengths.

4 0

3 years ago

Read 2 more answers

The following diagram represents a cart with an initial velocity of 1.0 m/s sliding along a frictionless track from point A

ki77a [65]

Answer:

point b

Explanation:

7 0

3 years ago

On a snowy day, max (mass = 15 kg) pulls his little sister maya in a sled (combined mass = 20 kg) through the slippery snow. max

sesenic [268]

Work done by a given force is given by

$W = F.d$

here on sled two forces will do work

1. Applied force by Max

2. Frictional force due to ground

Now by force diagram of sled we can see the angle of force and displacement

work done by Max = $W_1 = Fdcos\theta$

$W_1 = 12*5cos15$

$W_1 = 57.96 J$

Now similarly work done by frictional force

$W_2 = Fdcos\theta$

$W_2 = 4*5cos180$

$W_2= -20 J$

Now total work done on sled

$W_{net}= W_1 + W2$

$W_{net} = 57.96 - 20 = 37.96 J$

7 0

3 years ago

Water is pumped steadily out of a flooded basement at a speed of 5.4 m/s through a uniform hose of radius 0.83 cm. The hose pass

Gala2k [10]

To solve this problem it is necessary to apply the concepts related to the flow as a function of the volume in a certain time, as well as the potential and kinetic energy that act on the pump and the fluid.

The work done would be defined as

$\Delta W = \Delta PE + \Delta KE$