Answer:
<h2><u>Given </u><u>:</u><u>-</u></h2>- Mass = 1025 kg
- Acceleration = 9.8 m/s²
Force
<h2><u>Solution</u><u> </u><u>:</u><u>-</u></h2>We know that
F = mg
F = 1025 × 9.8
F = 10,045 N
Or,
10045/1000 = 10.045 Kilo Newton
Select the volume units that are greater than one liter.
2 answers:
Answer: The correct answers are option (a)and(c).
Explanation:
1) In ,1 kilo Liter = 1,000 Liter
1 liter = 0.001 kilo Liter
2) In ,1 Mega Liter = 1,000,000
1 Liter = Mega Liter
Where as milliliter, centiliter, deciliter and nano liters are smaller units that 1 liter
1 Liter = 1000 milliliter
1 Liter = 100 centiliter
1 Liter = 10 deciliter
1 Liter = nano liter
Hence, the correct answers are option (a)and(c).
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Answer:
20 m/s
Explanation:
Recall that one of the equations of motions can be written:
v = u + at, (also see attached for reference)
Where,
v = final speed (we are asked to find this)
u = initial speed = 0 (because it starts from rest)
t = time taken = 5s
We simply substitute the given values into the equation:
v = u + at
v = 0 + (4)(5)
v = 20 m/s
First put the speed in m/s. 120km/h = 33.33m/s. Now the position function is the integral of velocity, and velocity is in turn the integral of acceleration. The velocity is:
Now we integrate this expression to get the position. The constant of integration will be the distance the truck travels.
Here we set the distance, 35m as negative because I assumed the stopping point of the truck is the origin. Putting t=0 shows it starts at -35m.
Now solve the following equation for the time, t using the quadratic equation:
and choose the value t=1.149s
Now we integrate this expression to get the position. The constant of integration will be the distance the truck travels.
Here we set the distance, 35m as negative because I assumed the stopping point of the truck is the origin. Putting t=0 shows it starts at -35m.
Now solve the following equation for the time, t using the quadratic equation:
and choose the value t=1.149s