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KIM [24]
3 years ago
5

An engine develops 500 Nm of torque at 3900 rev/min. The power developed by the engine is ...

Physics
1 answer:
Oduvanchick [21]3 years ago
3 0

Answer:

204kW

Explanation:

P = t x ω = 500 x (2πx3900/60) = 204203W = 204kW

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<em>The magnitude of the force is 10 N</em>

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