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frez [133]
3 years ago
8

Which muscle group works the hardest (isometrically) when performing a wrist curl in the pronated position?

Physics
2 answers:
Elenna [48]3 years ago
6 0
Hello!
I believe its A. wrist flexors but im not exactly sure because it might be B. wrist extensors.
vaieri [72.5K]3 years ago
3 0
I believe the answer is b. wrist extensors because the question asks which works hardest and the angle of movement is greater for an extension in pronated position than a flexor  
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The octet rule states that in chemical compounds atoms tend to have
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Answer:

In chemical compounds, atoms tends to have the electron configuration of a noble gas.

Explanation:

The noble gases are unreactive because of their electron configurations. This noble gas neon has the electron configuration of 1s22s22p6 . It has a full outer shell and cannot incorporate any more electrons into the valence shell.

The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas. An exception to an octet of electrons is in the case of the first noble gas, helium, which only has two valence electrons.

4 0
3 years ago
Read 2 more answers
a trolley of mass 20kg was originally at rest on a smoth horizontal surface. bu how much will it accelerate if a pulling force o
DochEvi [55]

Answer:

just divide 22 N by 20 kg to get the acceleration in m/s2

Explanation:

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3 years ago
A person makes a cup of coffee by first placing a 200 W electric immersion heater in 0.32 kg
alexdok [17]

Answer:

Answer is D. 8.04 x 10^4 J

Explanation:

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8 0
3 years ago
Does Ap Physics have anything to do with probablity?
padilas [110]
So I'm a junior. I am currently taking AP Calc BC and AP Physics B.

As of now, I'm not sure if I should take AP Probability and Statistics or Differential Equations/Calc III next year. Also, I'm debating between taking AP Physics C or AP Chemistry.

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5 0
4 years ago
A wheel starts from rest and rotates with constant angular acceleration to reach an angular speed of 11.1 rad/s in 2.99 s.(a) fi
elena55 [62]
The angular acceleration of a rotating object is given by
\alpha =  \frac{\omega_f - \omega_i}{\Delta t}
where
\omega_f is the final angular speed of the object
\omega_i is its initial angular speed
\Delta t is the time taken to accelerate

For the wheel in our problem, \omega_f=11.1 rad/s, \omega_i = 0 and \Delta t=2.99 s, so its angular acceleration is
\alpha= \frac{11.1 rad/s-0}{2.99 s}=3.71 rad/s^2
8 0
3 years ago
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