Answer:
C. 150 N to the left
Explanation:
If we take right to be positive and left to be negative, then:
∑F = -450 N + 300 N
∑F = -150 N
The net force is 150 N to the left.
Answer:
12.974 m/s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
g = Acceleration due to gravity = 9.81 m/s²
= Coefficient of friction =0.66
a = Acceleration =
Car's original speed before braking was 12.974 m/s
<span>The equation for momentum is p = mv, where m is the mass of the object and v is its velocity. Through conservation of momentum, we know that the momentum of the rifle must be of the same magnitude and opposite direction to that of the bullet. Thus we can form two expressions for the respective momenta, set them equal, and solve for the recoil speed of the rifle.
718*0.0159 = vr*5.05 where vr is the rifle recoil speed.
Solving for vr = 718*0.0159/5.05 = 2.26 meters/second.</span>
Force on a proton when they are moving inside the magnetic field is given by
so here while protons are going upwards we can say its direction of velocity is towards +Y and magnetic field is towards us which is along +Z direction so they will have force due to this motion.
As per above equation of force we can have direction of force which is along +X direction.
So here both proton will bend towards +X direction and start moving in curved path.
Answer:
Question A:17.92 m/s
Question B:0.6 seconds
Explanation:
Question A:
Initial velocity(u)=24m/s
Height(h)=13m
acceleration due to gravity(g)=9.8m/s^2
Final velocity=v
v^2=u^2-2xgxh
v^2=24^2-2x9.8x13
v^2=24x24-2x9.8x13
v^2=576-254.8
v^2=321.2
Take them square root of both sides
v=√(321.2)
v=17.92m/s
Question B:
velocity(v)=17.92m/s
Acceleration due to gravity(g)=9.8m/s^2
Initial velocity(u)=24m/s
Time=t
v=u-gxt
17.92=24-9.8xt
Collect like terms
9.8t=24-17.92
9.8t=6.08
Divide both sides by 9.8
9.8t/9.8=6.08/9.8
t=0.6 approximately