Step by step solution :
standard deviation is given by :

where,
is standard deviation
is mean of given data
n is number of observations
From the above data, 
Now, if
, then 
If
, then 
if
, then 
If
, then 
If
, then 
so, 



No, Joe's value does not agree with the accepted value of 25.9 seconds. This shows a lots of errors.
The answer to life is how ever you make it...... you can do anything with life that you would like.................. But make your choices worth it......
Answer:
and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..
Explanation:
Expression for rate law for first order kinetics is given by:

where,
k = rate constant
t = age of sample
= let initial amount of the reactant
a = amount left after decay process
We have :


t = 95 s


Half life is given by for first order kinetics::


and 20.86 seconds are the values of the rate constant and the half-life for this process respectively..
Answer:
3 N to the right
Explanation:
There are two forces acting on the car:
- A force of 10 N towards the right
- A force of 7 N towards the left
Therefore, the net force is given by the difference between the two, since they are in opposite directions:

And the direction is to the right, since the force to the right has greater magnitude than the force to the left.
Bruh ima be honest with you idek