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Julli [10]
2 years ago
12

What does the model below represent?

Physics
1 answer:
Viefleur [7K]2 years ago
5 0

Answer:

D

Explanation:

Because we have two reactants and product

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Plz help will give 26 points !and be mark as brainliest !
Dimas [21]

<em>Answer: </em>

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4 0
3 years ago
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Two astronauts in space with a baseball decide to play catch to pass the time. In the language of conservation of momentum, desc
Anna35 [415]
As the first astronaut throws the ball, lets assume it goes with v velocity and the mass of the ball be m
the momentum comes out be mv, thus to conserve that momentum the astronaut will move opposite to the direction of the ball's motion with the velocity mv/M (where M is the mass of the astronaut).
4 0
4 years ago
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A skull believed to belong to an ancient human being has a carbon-14 decay rate of 5.4 disintegrations per minute per gram of ca
larisa86 [58]

Answer:

9.43*10^3 year

Explanation:

For this question, we ought to remember, or know that the half life of carbon 14 is 5730, and that would be vital in completing the calculation

To start with, we use the formula

t(half) = In 2/k,

if we make k the subject of formula, we have

k = in 2/t(half), now we substitute for the values

k = in 2 / 5730

k = 1.21*10^-4 yr^-1

In(A/A•) = -kt, on rearranging, we find out that

t = -1/k * In(A/A•)

The next step is to substitite the values for each into the equation, giving us

t = -1/1.21*10^-4 * In(5.4/15.3)

t = -1/1.21*10^-4 * -1.1041

t = 0.943*10^4 year

8 0
4 years ago
A 1500kg car is at rest before it accelerates when the light turns green. If it covers 45.0 meters in 15.0 seconds, what is the
lana [24]

Answer:

300N

Explanation:

Given parameters:

Mass of car  = 1500kg

Initial velocity  = 0m/s

Distance covered  = 45m

Time  = 15s

Unknown:

Net force applied  = ?

Solution:

From Newton's second law:

  Force  = mass x acceleration

  Force  = mass x \frac{v - u}{t}  

v is the final velocity

u is the initial velocity

t is the time taken

    Final velocity  = \frac{45}{15}   =3m/s

 Force  = 1500 x \frac{3 - 0}{15}   = 300N

8 0
3 years ago
The radius of the earth's very nearly circular orbit around the sun is 1.5×1011m. find the magnitude of the earth's velocity. as
Luden [163]
<span>Step 1 of 3 Calculate the magnitude of the earth’s velocity. The radius of earth orbit around the sun is . Time taken to complete one revolution is . Convert time from days into seconds. The expression for magnitude of earth velocity is, Substitute for , for . Further solved, Explanation | Common mistakes | Hint for next step Time taken to complete one resolution is 365 days. Convert time from days into seconds. Radius of earth orbit around the sun is given. Velocity is circumference of orbit upon time taken in one resolution. Calculate the magnitude of earth velocity. Change unit of velocity to Step 2 of 3</span>
7 0
3 years ago
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