Answer:
1.736m/s²
Explanation:
According to Newton's second law;

where;
Fm is the moving force = 70.0N
Ff is the frictional force acting on the body

is the coefficient of friction
m is the mass of the object
g is the acceleration due to gravity
a is the acceleration/deceleration
The equation becomes;

Substitute the given parameters

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²

The rate of change of velocity per unit time is called acceleration.
Its SI unit is m/s².

Answer:
it is very hard question for me sorry i cant solve it
As momentum / time = force
so; time = 100÷15
so your answer is 6.7 !!